Electricity Experiment (Internal Resistance)

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Homework Help Overview

The discussion revolves around an experiment to determine the internal resistance of a DC power supply using an ammeter, voltmeter, and variable resistor. Participants are exploring the setup and methodology for conducting the experiment effectively.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the arrangement of components in the circuit and the significance of measuring current and voltage. Questions arise about the role of the variable resistor and the necessity of disconnecting a resistor to obtain measurements. There is also inquiry into the definitions of terms like internal resistance and emf.

Discussion Status

The discussion is active, with participants providing various interpretations of the experimental setup and the relationships between the measured quantities. Some guidance has been offered regarding the connections and measurements needed, but there is no explicit consensus on a complete method.

Contextual Notes

Participants are working within the constraints of a homework assignment, and there is a focus on understanding the relationships between current, voltage, and resistance without providing a definitive step-by-step solution.

leviathanX777
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1. Hi I'm going to a physics Summer camp but they asked me to carry out my own experiment. This is because my dad's a physics teacher and he has a lot of equipment readily available to him. I have to find the internal resistance of a dc power supply with the following equipment given:
Power Supply
Ammeter
Voltmeter
Variable Resistor




2. V=IR



3. I don't know if I need more equations but would love to hear some feedback on how to do this!

Thanks.
 
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Connect DC power supply, ammeter and variable resistor in series. Connect volt meter parallel to the variable resistor.
Unplug a resistance R1 and find the current I1 and voltage V1.
I1 = V1/R1 = E/(R1 + r). repeat the same thing for another resistor. Solve the two equations to get the internal resistance of power supply.
 
So I'm guessing r is the internal resistance and E is the emf(voltage)? Why do I ahve to unplg the resistor in the first place to find the current and voltage?
 
What is the use of variable resistor?
 
To find different resistances, thus find different currents and voltages to get the average? Is little r internal resistance? So can you give me a step by step guideline for the experiment?
 
Well. connect DC power supply, ammeter and variable resistance in series. Set the variable at one position. Note down the ammeter reading. Note down the voltage V1 across variable resistor using volt meter. Let I1 be the current, . Repeat the same thing for another position of the variable resistor.
You can also write E = V1 + I1r = V2 + I2r, and find r
 

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