Electrodynamics flux calculation question

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Homework Help Overview

The discussion revolves around calculating the electric flux through a conical surface using Gauss's law. The problem involves a right circular cone with a point charge positioned at a specific height, prompting participants to explore the mathematical implications of the setup.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants express confusion regarding the normal vector and electric field calculations. There are inquiries about the appropriate coordinate system to simplify the integral, particularly cylindrical coordinates, and the limits associated with them. Some suggest visualizing the problem through diagrams to clarify the geometry involved.

Discussion Status

The conversation is ongoing, with participants actively seeking clarification on the geometry and mathematical setup. Some have suggested drawing diagrams to aid understanding, while others are exploring different coordinate systems and their implications for the problem.

Contextual Notes

Participants are grappling with the specifics of the problem setup, including the position of the charge and the geometry of the cone. There is a noted emphasis on the importance of visual aids in understanding the relationships between the elements involved.

AHSAN MUJTABA
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Homework Statement
Consider a right circular cone placed such that the symmetry axis is
the z axis. The base of the cone is centered at the origin with a radius of R. The
pointed end of the cone is at the location z = h. A point charge q is placed at the point
(0, 0, h/3). Show that the integral form of the Gauss's law holds by computing the
flux over the conical surface.
Relevant Equations
integral(E.n da )=Q/e I need toprove it
I don't really know how to find it mathematically as I am really confused in finding the normal vector and finding the electric field as well.
pls help
 
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AHSAN MUJTABA said:
Homework Statement:: Consider a right circular cone placed such that the symmetry axis is
the z axis. The base of the cone is centered at the origin with a radius of R. The
pointed end of the cone is at the location z = h. A point charge q is placed at the point
(0, 0, h/3). Show that the integral form of the Gauss's law holds by computing the
flux over the conical surface.
Relevant Equations:: integral(E.n da )=Q/e I need toprove it

I don't really know how to find it mathematically as I am really confused in finding the normal vector and finding the electric field as well.
pls help
Welcome to PhysicsForums. :smile:

It seems like a pretty straightforward surface integration, no? What coordinate system do you think you can choose to make the integral a little easier?

Also, when typing equations into the PF Edit window, it's best to use the Latex Guide that is linked at the bottom of the window to help you type your math equations in a much more readable form. For example, Gauss' Law:

https://en.wikipedia.org/wiki/Gauss's_law

1601759102329.png
 
I am actually pretty confused because If I take cylinderical coordinates then what would be limits of R and I am also confused by the position of charge at h/3
 
Can you show the calculation if the surface were just a sphere centered at the origin and the charge was at the origin? (use spherical coordinates)

And then can you show the calculation if the surface were a cylinder centered at the origin, and the charge was at the origin? (use cylindrical coordinates)
 
AHSAN MUJTABA said:
I am actually pretty confused because If I take cylinderical coordinates then what would be limits of R and I am also confused by the position of charge at h/3
Your first step, as ever, is a diagram. In this case, just a vertical slice through the middle, to produce a triangle. Draw a field line from the charge to the cone. Relate the angle of incidence to the angle, θ, the field line makes to the z axis.
Draw a second line at θ+dθ.
Consider the surface element these delimit rotated around the z axis to produce a band. What is the net field through it?
 
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do we have to take the cos component of electric field. I am still confused regarding the geometry.
 
AHSAN MUJTABA said:
do we have to take the cos component of electric field. I am still confused regarding the geometry.
Did you draw the diagram I described? Remember, it is a right circular cone.
Please post your diagram, labelling the origin, the point charge, the tip of the cone, the points where the two field lines meet the surface of the cone, and some angles.
 

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