# Archived Electromagnetic Induction of ac generator

1. Oct 7, 2008

1. The problem statement, all variables and given/known data
The coil of an ac generator has an area per turn of 1.2x10-2m2 and consists of 500 turns. The coil is situated in a 0.13-T magnetic field and is rotating at an angular speed of 34 rads/s. What is the emf induced in the coil at the instant when the normal to the loop makes an angle of 27 degrees with respect to the direction of the magnetic field?

2. Relevant equations
E=NAB$$\varpi$$sin$$\varpi$$t

3. The attempt at a solution
after plugging in the numbers into the equation I got 75 V. The answer is 12V

2. Apr 19, 2016

### cesca97

So you're on the right track you do use the equation E=NABw(sin(wt)) but I don't know how you got 75V. Its a simple plug and chug: E= (500)(1.2x10^-2)(0.13)(34)(sin (27))= 12.03V

3. Apr 20, 2016

### Gordianus

The ratio of 75 to 12 is 6.25, very close to 2*pi. Perhaps the error stems from confusing f with omega?