- #1

- 377

- 24

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- I
- Thread starter kelly0303
- Start date

- #1

- 377

- 24

- #2

dRic2

Gold Member

- 830

- 208

aren't you supposing too much ? You previously said that only the projection on the axis is constant, that's it. Why are you supposing the precession angle to be constant also ?So the way I visualize this, vectorially, is a vector corresponding to the angular momentum, that rotates at an angle around the internuclear axis (similar to a magnetic moment around a magnetic field). So the magnitude and precession angle seem to be constant (and hence the projection).

- #3

- 377

- 24

Sorry, we also have that the ##L^2## operator commutes with the Hamiltonian, so I assumed that the length of the vector is constant.I'm not familiar with this topic, hope I don't say something illy, but here

aren't you supposing too much ? You previously said that only the projection on the axis is constant, that's it. Why are you supposing the precession angle to be constant also ?

- #4

dRic2

Gold Member

- 830

- 208

- #5

Twigg

Science Advisor

Gold Member

- 547

- 270

Share: