Electron in a box - calculate the spring constant

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SUMMARY

The discussion focuses on calculating the spring constant for an electron in a box with energy levels of 1.5 eV and 2.1 eV. The energy levels correspond to quantum states 5 and 6, derived from the equation E[n]=n^2*E[0]. The fundamental energy equation is given as E[0] = (h^2)(pi^2)/2(m)(L^2), where h is Planck's constant, m is the mass of the electron, and L is the length of the box. The relationship between energy levels indicates a direct connection to quantum mechanics and wave functions.

PREREQUISITES
  • Understanding of quantum mechanics, specifically the particle-in-a-box model.
  • Familiarity with energy quantization and the concept of quantum states.
  • Knowledge of Planck's constant and its application in energy calculations.
  • Basic proficiency in algebra and manipulation of equations.
NEXT STEPS
  • Study the derivation of the particle-in-a-box model in quantum mechanics.
  • Learn about the implications of energy quantization on wave functions.
  • Explore the relationship between energy levels and spring constants in quantum systems.
  • Investigate the application of the Schrödinger equation in calculating energy states.
USEFUL FOR

Students and educators in physics, particularly those focusing on quantum mechanics and wave functions, as well as researchers interested in the properties of electrons in confined systems.

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Homework Statement


Electron in a box has 2 sequential energy levels of 1.5 eV and 2.1 eV
Calculate the spring constant


Homework Equations


E[n]=n^2*E[0]
Therefore, 2.1/1.5 = 1.4 = (6^2)/(5^2) and the quantum levels are 5 and 6
E[0] = (h^2)(pi^2)/2(m)(L^2)

The Attempt at a Solution


What is the "spring constant" for the wave equation??
 
Physics news on Phys.org
I think the question is connected to the time dependence of the wave function, but I am not sure...

ehild
 

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