Electron in a field: Canonical momentum versus kinematical momentum

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SUMMARY

The discussion clarifies the definitions of canonical momentum and kinematical momentum in the context of an electron in a laser field. In the length gauge, kinematical momentum equals canonical momentum (k = p), while in the velocity gauge, kinematical momentum is defined as canonical momentum plus the vector potential (k = p + A). The canonical momentum is derived from the Lagrangian with respect to velocity, particularly in systems without magnetic fields where it simplifies to kinematic momentum (p = mv). In magnetic fields, the vector potential contributes to the canonical momentum, altering its relationship with kinematical momentum.

PREREQUISITES
  • Understanding of the Schrödinger equation
  • Familiarity with Lagrangian mechanics
  • Knowledge of vector potentials in electromagnetic fields
  • Basic concepts of kinematics and dynamics of charged particles
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  • Study the derivation of the Schrödinger equation in both length and velocity gauges
  • Explore the role of vector potentials in classical and quantum mechanics
  • Learn about the implications of canonical momentum in systems with magnetic fields
  • Investigate the relationship between Lagrangian mechanics and Hamiltonian mechanics
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Physicists, particularly those specializing in quantum mechanics and electromagnetism, as well as students seeking a deeper understanding of momentum concepts in charged particle dynamics.

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Can anyone explain to me the definition of canonical and kinetic momentum?

The Schrödinger equation for an electron in a laser field can be written in the length gauge or the velocity gauge.
In the litterature it is often said that in the length gauge the kinematical momentum is equal to the canonical momentum k=p, while in the velocity gauge the kinematical momentum is the canonical momentum added by the vector potential k=p+A.

Can anyone elaborate on this or has any ref I can look at?
 
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The canonical momentum is defined as the derivative of the Lagrangian with respect to velocity. In a system where the potential doesn't have a velocity dependence (ie. one that doesn't have a magnetic field), this will just be the kinematic momentum, p = mv.

For a system with a charged particle in a magnetic field, the potential will have a term with the dot product of the velocity with the vector potential. So when you take a derivative with respect to velocity, in addition to the mv that you get from the kinetic energy, you also get a contribution from the vector potential.

See here for example:
http://galileo.phys.virginia.edu/classes/752.mf1i.spring03/ParticleMagneticField.htm
 

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