Electron moving inside a region of homogeneous electric field

Click For Summary
SUMMARY

The discussion focuses on the motion of an electron in a homogeneous electric field, specifically analyzing its velocity and energy conservation. The initial velocity of the electron is given as Vo=0.6C, where C is the speed of light. The calculations reveal that the final velocity, Vf, after exiting the electric field is Vf=0.6√2C, and the relationship between initial and final energy states is expressed through the equations Ei=γi.Eo and Ef=γf.Eo, with γi=5/4 and γf=5/(2√7). The participant confirms that conservation of momentum in the x-direction remains valid despite the perpendicular electric field.

PREREQUISITES
  • Understanding of relativistic mechanics and Lorentz transformations
  • Familiarity with electric fields and their effects on charged particles
  • Knowledge of energy conservation principles in physics
  • Basic proficiency in vector analysis and trigonometry
NEXT STEPS
  • Study the implications of Lorentz force on charged particles in electric fields
  • Learn about relativistic momentum and its conservation laws
  • Explore the concept of electric potential energy and its calculations
  • Investigate two-dimensional motion of particles in electromagnetic fields
USEFUL FOR

Physics students, educators, and professionals interested in relativistic dynamics and electric field interactions with charged particles.

Moara
Messages
43
Reaction score
5
Homework Statement
An electron moving with velocity Vo=0,6C where C is light speed, enters in a region with uniform Electric Field, E, perpendicular to the vector Vo. When the electron leaves this region, it's velocity makes an angle of π/4 with it's inicial direction.
a) find velocity of electron after leaving the region with the electric Field.
b) find the distance d shown in the figure if E is the electric Field and Eo is the rest energy of the electron
Relevant Equations
Etot^2=(pc)^2+Eo^2
U=Ed
W(electric)=Ue
15756379667116935560466080301347.jpg

a) since the eletric field is perpendicular to the inicial velocity, the x component is constant, hence Vf.cos45=Vo. This gives Vf=0,6√2.C
b) Ei=γi.Eo , γi=5/4 , Ef=γf.Eo , γf=5/(2√7)
Finally, Ei+e.E.d=Ef. Apparently this is incorrect, why??
 
Physics news on Phys.org
Moara said:
Homework Statement:: An electron moving with velocity Vo=0,6C where C is light speed, enters in a region with uniform Electric Field, E, perpendicular to the vector Vo. When the electron leaves this region, it's velocity makes an angle of π/4 with it's inicial direction.
a) find velocity of electron after leaving the region with the electric Field.
b) find the distance d shown in the figure if E is the electric Field and Eo is the rest energy of the electron
Homework Equations:: Etot^2=(pc)^2+Eo^2
U=Ed
W(electric)=Ue

View attachment 253750
a) since the eletric field is perpendicular to the inicial velocity, the x component is constant, hence Vf.cos45=Vo. This gives Vf=0,6√2.C
b) Ei=γi.Eo , γi=5/4 , Ef=γf.Eo , γf=5/(2√7)
Finally, Ei+e.E.d=Ef. Apparently this is incorrect, why??

You have a two-dimensional relativistic scenario here. The acceleration is not in general parallel to the force.
 
  • Like
Likes   Reactions: Moara
Did you manage to solve this?
 
PeroK said:
Did you manage to solve this?
Yes, found out that conservation of momentum in x is still valid, thank you
 

Similar threads

  • · Replies 17 ·
Replies
17
Views
3K
Replies
8
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 25 ·
Replies
25
Views
5K
  • · Replies 10 ·
Replies
10
Views
7K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
1
Views
1K