Electron orbiting proton-orbital radius?

  • Thread starter Thread starter awertag
  • Start date Start date
  • Tags Tags
    Electron Radius
Click For Summary

Homework Help Overview

The discussion revolves around calculating the orbital radius of an electron in the Bohr model, given its speed. The problem is situated within the context of atomic physics, specifically focusing on electron behavior in relation to protons.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of equations related to circular motion and electrostatic forces to find the orbital radius. There is an exploration of the implications of negative values for radius and the significance of charge signs in calculations.

Discussion Status

The conversation has progressed through various attempts to calculate the radius, with some participants correcting initial errors and arriving at a positive value. There is acknowledgment of potential inaccuracies in the final result, and participants express uncertainty about the correctness of their calculations.

Contextual Notes

Participants note the importance of correctly interpreting scientific notation and the implications of charge signs in their calculations. There is an ongoing examination of the assumptions made in the problem setup.

awertag
Messages
63
Reaction score
0
Electron orbiting proton--orbital radius??

Homework Statement




In the Bohr model, the electron is imagined to move in a circular orbit about a stationary proton. If the speed of the electron were 8.9e5 m/s, what would be the corresponding orbital radius?

2. Homework Equations



3. The Attempt at a Solution
Fe=ma
a=Fe/m
(v^2)/r=(kqq/r)/m
v^2rm=kqq
(8.9e5)(r)(9.11e-31)=(9e9)(1.6e-19)(-1.6e-19)
r=-2.842e-4m

I hope you can help!

--aweg
 
Physics news on Phys.org


awertag said:

Homework Statement




In the Bohr model, the electron is imagined to move in a circular orbit about a stationary proton. If the speed of the electron were 8.9e5 m/s, what would be the corresponding orbital radius?

2. Homework Equations



3. The Attempt at a Solution
Fe=ma
a=Fe/m
(v^2)/r=(kqq/r2)/m
v^2rm=kqq
(8.9e5)2 (r)(9.11e-31)=(9e9)(1.6e-19)(-1.6e-19)
r=-2.842e-4m

I hope you can help!

--aweg
Some corrections are in red above.

Also, r should not be negative. There's one more error above which made r come out to be negative.

I assume you mean 10‒4 when you write e‒4, etc.
 


is the other error that i included the sign for electron charge?
 


ok well now i got r=3.193e-10 meters which is positive, so that's good...but I'm pretty sure it's not right, either
 


and yes e5 is x10^5
 


oh just kidding that was correct! :D thank you so much!
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
8K
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
5
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K