Electron Properties: Electric vs Magnetic Fields

AI Thread Summary
Electrons can be deflected using either electric or magnetic fields, with the electric force being stronger for non-relativistic speeds. In relativistic scenarios, both forces are approximately equal. The discussion highlights that while deflecting electrons, the choice between electric and magnetic fields depends on the available energy sources, such as high voltages or currents. It is emphasized that energy conservation is crucial, as the kinetic energy of the electrons is altered when they interact with electric fields, unlike in magnetic fields where only trajectory changes occur. Ultimately, the energy required for deflection is context-dependent, influenced by the specific conditions of the system.
Mihai Dinu
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We can deflect a moving electron using an electric field or using a magnetic field. In order to obtain the same deviation, when the energy we should use is higher? Or, in other words, the "electric" or the "magnetic" property is stronger?
 
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Mihai Dinu said:
In order to obtain the same deviation, when the energy we should use is higher?
What about conservation of energy?
 
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Take a look at https://en.wikipedia.org/wiki/Lorentz_force
For electrons moving less than the speed of light (always the case), the electric force is stronger. But for relativistic electrons, the forces are about equal.
 
Khashishi said:
the electric force is stronger

Only if B = E in those particular units.
 
I try to choose the "cheapest energetic" way to deflect an electron, based on its known interactions. The electron has, also, a mass. Hypothetically, I could obtain same deflection as in previous case using this time gravitational attraction of another mass. How can this mass be compared with previous cases in terms of energy effort?
 
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Mihai Dinu said:
I try to choose the "cheapest energetic" way to deflect an electron, based on its known interactions.
Let me repeat myself: What about conservation of energy?
 
DrClaude said:
Let me repeat myself: What about conservation of energy?
I understand. To obtain a certain same deviation, I have use the same energy, no matter what form it has.
 
Mihai Dinu said:
I understand. To obtain a certain same deviation, I have use the same energy, no matter what form it has.
Yes :smile:
 
I need a bit of help with this. No work need be done on an object if its motion is circular. If we had a fixed pivot and a length of string, the Force X Distance would be zero. Where is the difference with circular motion in a magnetic field? Or are we discussion the Energy needed to set up the field?
 
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Vanadium 50 said:
Only if B = E in those particular units.
Yeah. That's the case in any reasonable system of units, in which electricity and magnetism are unified. Kind of hard to talk about an electromagnetic field, when the electric and magnetic fields have different dimensions.
 
  • #11
As far as deflecting electrons, if you have high voltages handy, electric fields are usually a good option. But if it's easier to provide high currents then electromagnets might be a better choice. Neither type of force field is intrinsically stronger.
 
  • #12
David Lewis said:
As far as deflecting electrons, if you have high voltages handy, electric fields are usually a good option. But if it's easier to provide high currents then electromagnets might be a better choice. Neither type of force field is intrinsically stronger.
When the electron pass between the plates of a polarized (ideal) capacitor, the electric field modifies the trajectory of this electron. One billion electrons can follow and the capacitor field will be unchanged. Some work is done. Where comes this energy from?
 
  • #13
Mihai Dinu said:
When the electron pass between the plates of a polarized (ideal) capacitor, the electric field modifies the trajectory of this electron. One billion electrons can follow and the capacitor field will be unchanged. Some work is done. Where comes this energy from?

Why isn't this obvious that it comes from the E-field? Turn off the field, no deflection.

Zz.
 
  • #14
ZapperZ said:
Why isn't this obvious that it comes from the E-field? Turn off the field, no deflection.

Zz.
I can not turn off the field, because it comes from the electrons of one plate and the ions of the other plate, and their number is not changed, no matter how many free electrons cross this field.
 
  • #15
Mihai Dinu said:
I can not turn off the field, because it comes from the electrons of one plate and the ions of the other plate, and their number is not changed, no matter how many free electrons cross this field.

You missed the entire point of my post!

Zz.
 
  • #16
ZapperZ said:
You missed the entire point of my post!

Zz.
I tried to understand: Free electrons that cross the capacitor static field change trajectories, so work is done, but the capacitor field rest unchanged forever. Where comes the new energy from?
Now I think at this scenario: the incoming kinetic electron starts to interact with the capacitor field and transferes energy to capacitor field by disturbing one by one the electrons from the plates, upto the moment when the capacitor field starts to restore its minimum state and pushes out the disturbing electron. So the electron gets no new energy, only a new trajectory - if case.
 
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  • #17
Correct. No energy need be consumed in deflecting electrons. You could use a permanent magnet, for example. There may be an energy input required to maintain an electric field (replace charge leakage) or magnetic field (resistance of the coil).
 
  • #18
Mihai Dinu said:
I tried to understand: Free electrons that cross the capacitor static field change trajectories, so work is done, but the capacitor field rest unchanged forever. Where comes the new energy from?
Now I think at this scenario: the incoming kinetic electron starts to interact with the capacitor field and transferes energy to capacitor field by disturbing one by one the electrons from the plates, upto the moment when the capacitor field starts to restore its minimum state and pushes out the disturbing electron. So the electron gets no new energy, only a new trajectory - if case.

This is incorrect for electrons in electric field, and certainly not true for uniform electric field such as that found in between parallel plate capacitors. The electrons gain kinetic energy from the E-field. This is similar to projectile motion in uniform gravitational field. So it isn't just a change in trajectory, as is the case for uniform magnetic field. There IS KE change! It is how we accelerate charged particles in particle accelerators.

Zz.
 
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