Electronic field calculation of 2 wires

Click For Summary
The discussion focuses on calculating the electric field produced by two nonconducting wires with opposite charges at a specific point. The user seeks clarification on why they cannot integrate the electric field equation with given limits to find the solution. A key point raised is that the electric field is a vector quantity, which complicates the integration approach suggested. The conversation emphasizes the importance of considering vector components when calculating the resultant electric field. Understanding the vector nature of electric fields is crucial for accurately solving the problem.
ThiagoG
Messages
15
Reaction score
0

Homework Statement


2 1.2m nonconducting wires meet at a right angle. One segment carries +2.5*10-6 C of charge distributed uniformly along its length, and the other carries -2.5*10-6 C distributed uniformly along it. Find the magnitude and direction of the electric field these wires produce at point P, which is .06 m from each wire.

Homework Equations



|E|=|kQ/r2|

The Attempt at a Solution



I have the solutions manual so I don't care for knowing how to solve it. I just want to know as to why I can't take the integral of (kQ/2r)dr with limits from -.08485(the distance from P to the tip of the wire) to +.08485.
 
Physics news on Phys.org
ThiagoG said:
I have the solutions manual so I don't care for knowing how to solve it. I just want to know as to why I can't take the integral of (kQ/2r)dr with limits from -.08485(the distance from P to the tip of the wire) to +.08485.
Because that is not how to solve it - which you don't care to know.
Hint: E is a vector.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
14
Views
5K
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
Replies
3
Views
3K
Replies
17
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 12 ·
Replies
12
Views
4K
  • · Replies 20 ·
Replies
20
Views
3K