Electrons in a uniform electric field.

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SUMMARY

The discussion focuses on an experiment involving electrons in a uniform electric field created by two parallel plates, one positively charged and the other negatively charged. The anode voltage is set to 3,000 volts, and the relationship between the distance between the plates and the electric field strength is explored using the equation E = V/d. The derived equation y=(E/4V)x^2 is used to analyze the motion of electrons, with the graph indicating a power of approximately 1.7. The experiment's conditions, such as whether it was conducted in a vacuum or gas, are also questioned.

PREREQUISITES
  • Understanding of electric fields and potential difference
  • Familiarity with basic kinematics equations
  • Knowledge of electron behavior in electric fields
  • Experience with graphing and interpreting experimental data
NEXT STEPS
  • Study the principles of electric fields and their effects on charged particles
  • Learn about the operation and applications of electron guns
  • Explore the derivation and implications of the equation E = V/d
  • Investigate the impact of conducting experiments in vacuum versus gas environments
USEFUL FOR

Physics students, experimental researchers, and educators interested in the behavior of electrons in electric fields and practical applications of electrostatics.

lord_blurg
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Homework Statement



Basically, I am writing up a practical experiment dealing with Electrons in a uniform electric field (I.e. Using an electron gun).

There are two parallel plates, one with a positive charge and one with a negative charge. Between these to plates is a grid which allows for easy graphing.

It can be assumed that the electric field between the plates is uniform. A grid (with lines separated by 1 cm) is shown. I need to use this information to determine the distance, d, between the plates and to calculate the strength of the uniform electric field, E.

How do I find out the distance between the 2 parallel plates? (Probably simplistic, it's just that I am doing this experiment based on an experiment video I watched)

The anode voltage is set to 3,000 volts.
The graph I got was y=(.0504)(x)^1.763

Homework Equations



I am assuming this equation is related...

E = V/d (V is the potential difference between the plates.)
 
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Theoretically, the equation is y=(a/2/v^2)x^2

where, a is the acceleration=eE/m
v is the initial velocity, assumed to be parallel to the plates

If you substitute all these quantities to above equation then
y=eE/(2mv^2)x^2

and while mv^2/2=eV with V is the voltage

y=(E/4V)x^2

You do not need the distance between 2 plates.

Here you got the power of about 1.7<2. Hmm, was the experiment held in vacuum or in some gas?
 

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