# Electrons: Position, Exit Angle, 2 cm Length Plates

• MissJewels
The electron then has an upward velocity of 6.4x1014 m/s2 when it exits the area between the plates. The electron's vertical position is then 6.4x1014 m above the top of the plates.f

## Homework Statement

Electrons moving initially at 2.4 X 106 m / s in a horizontal direction. They enter a region between two plates of 2 cm in length and are subjected to an acceleration of 4x 1014 m/s2, vertical and pointing upwards. Determine:
a) the vertical position of the electrons as they exit the region between the plates
b) the exit angle

## Homework Equations

Honestly, I don't even know where to start with this, I have no idea what it looks like! Can someone explain it to me, at least, what Its asking, in english?

## The Attempt at a Solution

Can't even try, i don't get it.

## Homework Statement

Electrons moving initially at 2.4 X 106 m / s in a horizontal direction. They enter a region between two plates of 2 cm in length and are subjected to an acceleration of 4x 1014 m/s2, vertical and pointing upwards. Determine:
a) the vertical position of the electrons as they exit the region between the plates
b) the exit angle
This is a projectile motion problem. But, instead of the acceleration being g=9.8 m/s2, it is 4x1014 m/s2, downward.
Also, each electron travels 2 cm for the horizontal displacement, and we are given the initial velocity.

Hope that helps.

This is a projectile motion problem. But, instead of the acceleration being g=9.8 m/s2, it is 4x1014 m/s2, downward.
Also, each electron travels 2 cm for the horizontal displacement, and we are given the initial velocity.

Hope that helps.

Yes it does help, very much so! Thank you! I'll try that :)

This is a projectile motion problem. But, instead of the acceleration being g=9.8 m/s2, it is 4x1014 m/s2, downward.
Also, each electron travels 2 cm for the horizontal displacement, and we are given the initial velocity.

Hope that helps.

I still don't understand the 2 cm long plates buisiness though... can't seenm to picture what it looks like?

It would look something like this:
[PLAIN]http://teachers.sduhsd.k12.ca.us/gstimson/charonplatesPphys5.gif[/INDENT][/INDENT] [Broken]
Each electron is starts out moving horizontally and passes in between the two square plates, say moving from left to right. When an electron is in between the two plates, it has an acceleration 4x1014 m/s2 downward. When it is outside of the plate area it has an accleration of g = 9.8 m/s2, which can be ignored in comparison to the 4x1014 m/s2 acceleration.

In this problem, the square plates have a side length of 2 cm. Therefore the electron only experiences the 4x1014 m/s2 acceleration over a horizontal distance of 2 cm, i.e. while it is in the area between the two plates.​

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