(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Identical isolated conducting spheres 1 and 2 have equal charges and are separated by a distance that is large compared with their diameters (Fig. 21-22a). The magnitude of the electrostatic force acting on sphere 2 due to sphere 1 is F = 6.5 N. Suppose now that a third identical sphere 3, having an insulating handle and initially neutral, is touched first to sphere 1 (Fig. 21-22b), then to sphere 2 (Fig. 21-22c), and finally removed (Fig. 21-22d). What is the magnitude of the electrostatic force F' that now acts on sphere 2?

2. Relevant equations

F = (Q1*Q2)K/r^2

3. The attempt at a solution

so each touch takes away half the total charge in the beginning right?

first i thought it was half taken away from each sphere

so the final would be Q1 = Q1/ 2 and Q2 = Q2/2 and since theyre the same

i just combined them and made it Q1 *Q2 = Q/4

k is constant

r^2 is constant

so i though the answer would be 6.5/ 4

......but it's not

am i thinking the right way? what am i doing wrong?

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# Homework Help: Electrostatic force of Repulsion

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