Electrostatic Potential Energy-related.

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Tarabas
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Homework Statement


E=(1/4πε0)(Q/r^2) for R<r<2R

Homework Equations


U= integral (2R,R) ( (ε0 E^2)/2*4πr^2 dr

The Attempt at a Solution


I have no idea where the U-formula comes from. Any help would be appreciated.
I added some pictures so that it could be easier to understand.
12.jpg
123.jpg
 
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Hello Tarabas,

You might want to look through your textbook in the parts that talk about the energy stored in an electrostatic field. By that I mean the total energy it takes to create a given electrostatic field in the first place.

To point you in the right direction, the energy density (energy per unit volume) of an electrostatic field is

[tex]\frac{dU}{dV} = \frac{1}{2} \varepsilon_0 |E|^2[/tex]

where [itex]dU[/itex] is the differential potential energy (the potential energy of the space enclosed within the differential volume), [itex]dV[/itex] here refers to the differential volume (where '[itex]V[/itex]' here stands for volume, not to be confused with potential or voltage) and [itex]E[/itex] is the magnitude of the electric field at that point in space. Really though, you should check your textbook because it's likely there are at least a few pages dedicated to this idea.

Now do you see how the answer you posted in the image is integrating the energy density over the specified volume? :wink: [Edit: which gives you the energy stored in that region of space between [itex]R[/itex] and [itex]2R[/itex]]
 
Last edited:
collinsmark said:
Hello Tarabas,

You might want to look through your textbook in the parts that talk about the energy stored in an electrostatic field. By that I mean the total energy it takes to create a given electrostatic field in the first place.

To point you in the right direction, the energy density (energy per unit volume) of an electrostatic field is

[tex]\frac{dU}{dV} = \frac{1}{2} \varepsilon_0 |E|^2[/tex]

where [itex]dU[/itex] is the differential potential energy (the potential energy of the space enclosed within the differential volume), [itex]dV[/itex] here refers to the differential volume (where '[itex]V[/itex]' here stands for volume, not to be confused with potential or voltage) and [itex]E[/itex] is the magnitude of the electric field at that point in space. Really though, you should check your textbook because it's likely there are at least a few pages dedicated to this idea.

Now do you see how the answer you posted in the image is integrating the energy density over the specified volume? :wink: [Edit: which gives you the energy stored in that region of space between [itex]R[/itex] and [itex]2R[/itex]]

Thanks a lot. I actually checked my textbook and it was nowhere. :D