Electrostatics help please -- Electric field, potential

AI Thread Summary
Two spheres, one with a charge of -20 mC and the other with -50 mC, are positioned 5 meters apart, and the discussion focuses on calculating the electric field and potential at the halfway point. The relevant equations for the electric field from each sphere are provided, with suggestions to clarify the use of negative charges and to utilize LaTeX for better readability. Participants emphasize the importance of calculating the electric fields separately and considering their directions, as they may oppose or reinforce each other. Additionally, the formula for electric potential is mentioned, prompting further calculations for the potential at the halfway point. The conversation highlights the need for clear communication and understanding of the underlying physics principles.
RamirezA
Messages
3
Reaction score
0
New poster has been reminded to show their work on schoolwork problems
Homework Statement
Calculate the electric field (halfway point) and value of the electric potential at the halfway point
Relevant Equations
E=kQ1/r1^2
E=kQ2/r2^2
E=E1+E2
Hello, any answers appreciated:
'Two spheres are 5 m apart. Sphere 1 has a charge of -20 mC and sphere two has a charge of -50 mC. (a) Find the strength of the electric field at the sphere's halfway point. (b) Find the electric potential at the halfway point
 
Physics news on Phys.org
RamirezA said:
Homework Statement:: Calculate the electric field (halfway point) and value of the electric potential at the halfway point
Relevant Equations:: E=kQ1/r1^2
E=kQ2/r2^2
E=E1+E2

Hello, any answers appreciated:
'Two spheres are 5 m apart. Sphere 1 has a charge of -20 mC and sphere two has a charge of -50 mC. (a) Find the strength of the electric field at the sphere's halfway point. (b) Find the electric potential at the halfway point
Urgent or not, forum rules require you to post an attempt.
 
haruspex said:
Urgent or not, forum rules require you to post an attempt.
E1= (9x10^9)(10x10^-6)/(5)^2 (dont know where/if too include the negative values in this)
= 3600
E2= (9x10^9)(30x10^-6)/(5)^2
=10800
=14400
 
RamirezA said:
E1= (9x10^9)(10x10^-6)/(5)^2 (dont know where/if too include the negative values in this)
= 3600
E2= (9x10^9)(30x10^-6)/(5)^2
=10800
=14400
I don't claim to be any expert but I will try to give you a few hints.

First try using latex for your formulas/equations it is quite difficult to read without it,and a lot of people won't even bother reading through your question if you write it out like that.

Second the formula for the electric field is this;

$$ E = \frac{Q}{4\pi \epsilon0 r^2} $$ I am guessing the k in your formula is just the pi and epsilon put in one constant;

Now I am going to assume that you know what all of these are; that Q is your charge pi the value of pi (3.14) etc..

Now the distance between your spheers is 5 m, if you are asked to calculate the strength of the E field at the halfwaypoint,what is your distance then?

Also the - infront of your spheers mean that they are negative charged.

What I would do if I were you (for part a) is calculate E1 and E2 at the halfwaypoint and than try to get the ##E_{total} ##.

For all the homework helpers,if I am leading Ramirez astray,let him (and me) know,I am just going of the litle knowledge I have.
 
arhzz said:
I don't claim to be any expert but I will try to give you a few hints.

First try using latex for your formulas/equations it is quite difficult to read without it,and a lot of people won't even bother reading through your question if you write it out like that.

Second the formula for the electric field is this;

$$ E = \frac{Q}{4\pi \epsilon0 r^2} $$ I am guessing the k in your formula is just the pi and epsilon put in one constant;

Now I am going to assume that you know what all of these are; that Q is your charge pi the value of pi (3.14) etc..

Now the distance between your spheers is 5 m, if you are asked to calculate the strength of the E field at the halfwaypoint,what is your distance then?

Also the - infront of your spheers mean that they are negative charged.

What I would do if I were you (for part a) is calculate E1 and E2 at the halfwaypoint and than try to get the ##E_{total} ##.

For all the homework helpers,if I am leading Ramirez astray,let him (and me) know,I am just going of the litle knowledge I have.
Thanks man, that helps
 
RamirezA said:
Thanks man, that helps
Consider in what direction each field acts. Do they oppose each other or reinforce?
For part b, what is the formula for potential?
What answers do you get?
 
Thread 'Minimum mass of a block'
Here we know that if block B is going to move up or just be at the verge of moving up ##Mg \sin \theta ## will act downwards and maximum static friction will act downwards ## \mu Mg \cos \theta ## Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
TL;DR Summary: Find Electric field due to charges between 2 parallel infinite planes using Gauss law at any point Here's the diagram. We have a uniform p (rho) density of charges between 2 infinite planes in the cartesian coordinates system. I used a cube of thickness a that spans from z=-a/2 to z=a/2 as a Gaussian surface, each side of the cube has area A. I know that the field depends only on z since there is translational invariance in x and y directions because the planes are...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Back
Top