What is the percent CdSO4 by mass in a 1.0 molal aqueous solution? My attempt: CdSO4 is 208.47g/mol 1.0 molal = 1 mol CdSO4/1kgH2O Converted mols to grams, and kg to g. 208.47g Cd/1000g H2O = .20847 .20847 x 100 to get % mass = 20.8% It is an old test question that I am going over for finals week. I keep coming up with a different answer than what was on my test. I keep getting the value of 20.8%, which the answer listed on my test is 17.2%. Did my teacher make a failure in grading or did I just do something differently the first time around? I cant find my original work.