Elementary Topology Homework: Boundaries of (x,y) on y = |x-2| + 3 - x

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Homework Help Overview

The discussion revolves around determining the properties of the set of points (x,y) defined by the equation y = |x-2| + 3 - x, specifically focusing on whether the set is bounded or unbounded, closed or open, connected or disconnected, and what its boundary consists of.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the characteristics of the set, with one noting that the set appears unbounded based on a graph. Questions arise regarding the definitions of closed sets and connectedness, with some participants seeking clarification on these concepts.

Discussion Status

The discussion is ongoing, with participants providing insights and questioning each other's reasoning. There is a mix of agreement and challenge regarding the definitions and properties being discussed, particularly around the nature of closed sets and connectedness.

Contextual Notes

Some participants express uncertainty about the definitions of connectedness and the implications of the absolute value in the function, indicating a need for further exploration of these concepts.

tracedinair
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Homework Statement



Determine if the set of points (x,y) on y = |x-2| + 3 - x are bounded/unbounded, closed/open, connected/disconnect and what it's boundary consist of.

Homework Equations



The Attempt at a Solution



I know that the set is closed, and then by definition of a closed set it's boundary is itself. As far as bounded/unbounded goes, it seems unbounded when I graph it because I cannot see the entire graph. I'm unsure about connectedness and do not know how to determine it.

Any help is appreciated.
 
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Well, in (x,y) x is certainly not bounded. It runs from -infinity to infinity. To think about connectedness, do you see that the function is continuous? That means its graph is a continuous curve with no breaks in it, right? What's the definition of 'connected' that you are using?
 
tracedinair said:
I know that the set is closed, and then by definition of a closed set it's boundary is itself.

Just so you know, that's not true in general. A closed set contains its boundary. For example, the unit 2-ball [tex](x^{2} + y^{2})^{1/2} \leq 1[/tex] is closed but is not the same as its boundary which is the 1-sphere [tex](x^{2} + y^{2})^{1/2} = 1[/tex]. I could just be being pedantic though and you could well have known that and just not felt like spelling it out.
 
My guess then would that it is disconnected because of the absolute value in the function.
 
tracedinair said:
My guess then would that it is disconnected because of the absolute value in the function.

Guess?? Why are you guessing?? I'll ask you once more. What's the definition of a connected set?
 

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