Eliminating parameters and graphing parametric equations

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To eliminate the parameter from the given parametric equations x=t^2 and y=t-1, the relationship x=(y-1)^2 is derived. The main challenge discussed is determining the appropriate domain and range for graphing the resulting equation. The range of t from -1 to 3 translates to a specific range for y, which is crucial for accurate graphing. There is a suggestion to consider graphing x as a function of y for simplicity. Understanding these relationships is essential for successfully graphing the plane curve.
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Homework Statement


"Eliminate the parameter and graph the plane curve represented by the parametric equations."

x=t^2, y=t-1; -1 ≦ t ≦ 3

Homework Equations





The Attempt at a Solution


No need for you guys to graph; I can do that on my own. It would be a lot of work to have you guys graph something.

Solved t with the y equation. y-1 = t
Plugged that into x=t^2. Received x=(y-1)^2.
My problem is that I'm not sure how to find the domain/range so that I can properly graph it. Thanks.
 
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Supreme said:

Homework Statement


"Eliminate the parameter and graph the plane curve represented by the parametric equations."

x=t^2, y=t-1; -1 ≦ t ≦ 3

Homework Equations


The Attempt at a Solution


No need for you guys to graph; I can do that on my own. It would be a lot of work to have you guys graph something.

Solved t with the y equation. y-1 = t
Plugged that into x=t^2. Received x=(y-1)^2.
My problem is that I'm not sure how to find the domain/range so that I can properly graph it. Thanks.

Isn't that y+1=t? It's probably easier just to graph it as a function of t. If you want to graph it in x-y coordinates then you should think of x as a function of y.
 
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