Ella's question from Facebook (solving for a variable)

[Jameson]

I have 3 problems I'm stuck on. Anyone please help. B=1/9(one ninth)pi to the 2nd power t and trying to solve for t

Then this one, c=1/2(half)mr solving for m

And solve the formula for the indicated variable P=a+2b+4c, for a.

 

[Jameson]

1) I'm not sure exactly what you mean by this. Is this it?

[math]B=\frac{1}{9} \pi ^2 t[/math]

2) [math]c=\frac{1}{2}mr[/math]

Multiply both sides by 2.

[math]2c=1*m*r[/math] or just [math]2c=mr[/math]

Divide both sides by r.

[math]\frac{2c}{r}=m[/math] so [math]m=\frac{2c}{r}[/math]

3) $P=a+2b+4c$ and solve for $a$

Subtract $2b$ from both sides.

$P-2b=a+4c$.

Subtract $4c$ from both sides.

$P-2b-4c=a$ or $a=P-2b-4c$