Elliptic partial differential equation

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SUMMARY

The discussion focuses on solving an elliptic partial differential equation, specifically exercise 6.3, using equations 6.12 and 6.15 to derive 6.16. The user expresses difficulty in manipulating the equations, particularly when substituting the derivative phi' from equation 6.15. The proposed method involves collecting terms to simplify expressions involving phi'_i and phi_i, ultimately leading to the identification of terms like (phi'_i phi'_{i-1} - phi_i phi_{i-1}). The user is advised to apply the identity 2(ab - cd) = (a - c)(b + d) + (a + c)(b - d) for simplification.

PREREQUISITES
  • Understanding of elliptic partial differential equations
  • Familiarity with mathematical manipulation of equations
  • Knowledge of the specific equations 6.12, 6.15, and 6.16
  • Ability to apply algebraic identities in simplification
NEXT STEPS
  • Study the derivation and applications of elliptic partial differential equations
  • Review the mathematical identities for simplifying expressions
  • Practice solving similar exercises involving equations 6.12 and 6.15
  • Explore numerical methods for solving elliptic PDEs
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Students and researchers in applied mathematics, particularly those focusing on elliptic partial differential equations and their solutions.

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Hey guys, so my professor told me to take a look at an equation, because he thinks that there is a mistake. We are basically talking about exercise 6.3 (on last image). The pictures will show you the text, so that you have all the information, that I have
11568ce5b2.png

http://puu.sh/mrNDl/ec19cdff63.png
8d9fc16cc0.png

http://puu.sh/mrNF3/7461f97ad4.png

So... I should "just use" 6.12 and 6.15 to get 6.16.
The point is that I have no clue how to do this.
my attemp was
http://puu.sh/mJ1HR/08899e8813.png
but, this gets super ugly when I start to insert the phi' from 6.15 and calculate everything. Is this even the right idea ?
 
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I would concentrate on collecting up terms so that you get a lot of occurrences of ##\phi'_i-\phi_i##, and likewise with i-1.
You will find terms like ##(\phi'_i\phi'_{i-1}-\phi_i\phi_{i-1})##. Here you can use 2(ab-cd)=(a-c)(b+d)+(a+c)(b-d).
 

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