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StephenDoty
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When switch S in the figure is open, the voltmeter V of the battery reads 3.07 V. When the switch is closed, the voltmeter reading drops to 2.95 V, and the ammeter A reads 1.70 A. Assume that the two meters are ideal, so they do not affect the circuit.
Find the value of the emf. (see picture posted below)
the equation would be
E-Ir-IR
or E= I(r+R)
E=Ir
however I am totally confused on how to find the internal resistance value,r, when the switch is open and the value of R when the switch is close. Any help would be appreciated. Thanks. I apprecaite the help.
Stephen
Find the value of the emf. (see picture posted below)
the equation would be
E-Ir-IR
or E= I(r+R)
E=Ir
however I am totally confused on how to find the internal resistance value,r, when the switch is open and the value of R when the switch is close. Any help would be appreciated. Thanks. I apprecaite the help.
Stephen
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