Emission of a Photon: Origin and Role of Electron Constituents

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    Emission Photon
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SUMMARY

The emission of a photon occurs when an electron transitions to a lower energy level, resulting in the release of energy in the form of electromagnetic radiation. This process is governed by quantum electrodynamics, where the photon is produced during the transition rather than being pre-existing within the electron. The interaction responsible for this emission is described as a three-way interaction 'vertex', which does not involve any known constituents of the electron, as electrons are currently understood to lack sub-structure. The transition is characterized by a superposition of states, leading to the emission of a single photon corresponding to the energy difference between the involved states.

PREREQUISITES
  • Quantum Electrodynamics (QED)
  • Understanding of atomic energy levels
  • Concept of superposition in quantum mechanics
  • Knowledge of electromagnetic radiation principles
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  • Study the principles of Quantum Electrodynamics (QED)
  • Learn about atomic transitions and energy level diagrams
  • Explore the concept of superposition and its implications in quantum mechanics
  • Investigate the properties of electromagnetic radiation and photon emission
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Physicists, quantum mechanics students, and anyone interested in the fundamental processes of photon emission and atomic transitions.

  • #31
Only if you use the concept of relativistic mass, which is done in ancient textbooks and bad TV documentations only.
mass of electron in natural units is 0.511 Mev.
 
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  • #32
I don't see how your post is related to the others in this thread.
c=1 is a conventional choice, but this does not mean that my height is some nanometers.
 
  • #33
that is just a conventional way.To get back to original requires some work.And what you don't see.
 
  • #34
You are missing the point. E=mc² is wrong. The correct formula is E² = p²c² + (mc²)²
 
  • #35
K^2 said:
You are missing the point. E=mc² is wrong. The correct formula is E² = p²c² + (mc²)²
if you don't use the definition of relativistic mass then,right.Otherwise both are same.Energy is time component of four momentum and mass is invariant,so they are really different. if one avoids the notion of relativistic mass which is already abandoned then of course it is wrong.But that is just not what I say.It is a matter of definition.
 
  • #36
Fact that use of m as symbol for relativistic mass is outdated was the whole point of mfd's comment, and the reason for your reply to denisfl8 being at very least incomplete.

Mass, without qualifier, is assumed to be invariant mass. If you want to talk about relativistic mass, you should qualify that for clarity. Were you to reply that, "Energy is equivalent to relativistic mass," there would be no complaint.
 
  • #37
K^2 said:
Fact that use of m as symbol for relativistic mass is outdated was the whole point of mfd's comment, and the reason for your reply to denisfl8 being at very least incomplete.

Mass, without qualifier, is assumed to be invariant mass. If you want to talk about relativistic mass, you should qualify that for clarity. Were you to reply that, "Energy is equivalent to relativistic mass," there would be no complaint.
Oh,sorry for that.
 

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