Energy and charged particle collisions

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Homework Help Overview

The discussion revolves around calculating the initial velocity of an alpha particle in a collision with a gold nucleus, focusing on energy transformations and electric potential energy (EPE) in the context of charged particle interactions.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between kinetic energy (K_E) and electric potential energy (E_E), questioning the definitions and assumptions regarding initial velocity and energy states during the collision.

Discussion Status

There is ongoing clarification regarding the interpretation of initial velocity and the role of EPE. Some participants have provided insights into the nature of repulsive forces between charged particles and the implications for energy conservation at different points in the interaction.

Contextual Notes

Participants note the assumption that the gold nucleus remains stationary during the interaction and discuss the implications of this assumption on the calculations and energy considerations.

krbs
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Homework Statement


Find the initial velocity of an alpha particle with a mass of ##6.64 \times 10^{-27} kg## and a charge of ##+3.2 \times 10^{-19} C##, if it undergoes a head on "collision" with a gold nucleus. You may assume the gold nucleus does not move at all during the interaction. The charge on the gold nucleus is ##+2.53 \times 10^{-17} C## and the distance of closest approach between the two is ##4.7 \times 10^{-15} m##.

Homework Equations


##K_E\ =\ E_E##

or

##K_E\ +\ E_E\ =\ E_E##?

The Attempt at a Solution


I've already calculated initial velocity using ##K_E\ =\ E_E## and got ##6.8 \times 10^{7} m/s## but I suspect this is incorrect.

I'm having trouble understanding energy transformations during collisions of charged particles. I think that by "initial velocity" they mean just before the particles collide? In which case I should take into account EPE for the initial total energy. I think the final energy at the instant of closest approach must be entirely EPE because the gold nucleus is stationary and so the particles' combined velocity must be zero.
 
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krbs said:
I'm having trouble understanding energy transformations during collisions of charged particles. I think that by "initial velocity" they mean just before the particles collide? In which case I should take into account EPE for the initial total energy. I think the final energy at the instant of closest approach must be entirely EPE because the gold nucleus is stationary and so the particles' combined velocity must be zero.

You're correct on the second point, but not the first. If two particles repel each other, then (unless one has an initial velocity towards the other), they will simply move further apart. Unlike gravity, however, where the velocity gets larger until the two objects actually physically collide, the velocity during repulsion will decrease until the smaller particle stops and then goes back the way it came.
 
Last edited:
So initial velocity refers to the velocity of the particle when it's far away from the other, and EPE is negligible?
 
krbs said:
So initial velocity refers to the velocity of the particle when it's far away from the other, and EPE is negligible?
Yes, you have to assume EPE is negligible initially; otherwise, where it starts will affect the minimum distance.
 
Okay, thanks for your help
 

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