Energy and Entropy from P-V Diagram

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SUMMARY

The discussion focuses on solving thermodynamic problems related to an ideal monatomic gas undergoing a specific cycle defined by pressure and volume changes. The work done by the gas from state a to state c is calculated as 3 J, while the total change in internal energy during the complete cycle is 0 J. The change in internal energy from state b to c requires the use of the equation ΔU = nCvΔT, and the change in entropy from b to c can be determined using dS = dQ/T. The key to solving these problems lies in expressing ΔT in terms of ΔP and V.

PREREQUISITES
  • Understanding of ideal gas laws, specifically PV = nRT
  • Knowledge of thermodynamic equations, particularly ΔU = nCvΔT
  • Familiarity with entropy calculations using dS = dQ/T
  • Basic concepts of monatomic gases and their properties
NEXT STEPS
  • Learn how to derive ΔT in terms of ΔP and V for ideal gases
  • Study the integration of heat flow to calculate changes in entropy
  • Explore the implications of the first law of thermodynamics in cyclic processes
  • Investigate the specific heat capacities for different types of gases
USEFUL FOR

Students studying thermodynamics, physics enthusiasts, and anyone looking to deepen their understanding of gas behavior in thermodynamic cycles.

Rapier
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Homework Statement


An ideal monatomic gas is taken through the above cycle where p1= 2 X 105 Pa and V1 = 5 cm3. During the cycle both the pressure and volume will change such that p2 = 2 p1 and V2 = 4 V1.

a) How much work is done by the gas in going from state a to state c along path abc?
Wabc = 3 J
OK

b) What is the change in internal energy in going from b to c?
Ubc= J

c) What is the change in internal energy during the complete cycle?
UTOT = 0 J
OK

d) What is the change in entropy per mole of gas in going from b to c?
ΔSbc = J/K

e) What is the change in entropy per mole during the complete cycle?
ΔSTOT= 0 J/K
OK

I am having problems with Parts B and D.

Homework Equations


PV=NRT
Q = nCvdt


The Attempt at a Solution



I only have P and V. I cannot use the Ideal Gas Law to calculate n or T because I have two unknowns. I cannot use my Heat Equations because I am still missing n and T. I'm just stuck. If I can calculate B, I think I can get D...I just don't see any way to calculate the Heat in part B. HELP!

Thanks.
 

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Rapier said:
b) What is the change in internal energy in going from b to c?
Ubc= J
Use: ΔU = nCvΔT = n(3R/2)ΔT

Since PV = nRT, you can express ΔT in terms of ΔP and V (V is constant).

d) What is the change in entropy per mole of gas in going from b to c?
ΔSbc = J/K
Use: dS = dQ/T. What is the heat flow in terms of dT and Cv? Integrate that to get ΔS.

AM
 
Andrew Mason said:
Use: ΔU = nCvΔT = n(3R/2)ΔT

Since PV = nRT, you can express ΔT in terms of ΔP and V (V is constant).

Use: dS = dQ/T. What is the heat flow in terms of dT and Cv? Integrate that to get ΔS.

I can't believe I didn't see that. Once I read "express ΔT in terms of ΔP and V" it all fell together. It took me less than 2 minutes to solve the problems. Thanks! :)
 

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