Energy Balance Equation for Diffusion of Specimens Across a Membrane

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SUMMARY

The energy balance equation for the diffusion of specimens A and B across a membrane is defined by the heat flux resulting from their concentration and temperature differences. The equation is expressed as mA*(hA(TA)-hA(TB)) for specimen A and mB*(hB(TB)-hB(TA)) for specimen B, where mA and mB represent the diffusion fluxes, and hA and hB denote the specific enthalpies at respective temperatures TA and TB. This formulation assumes a steady-state condition during the diffusion process.

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lesy1
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Imagine a wall (membrane). Concentration of a specimen A on one side of the wall is cA and it has the temperature TA. The concentration of a specimen B on another side of the wall is cB and it has the temperature TB. Specimen A nad B diffuse against each other (assume steady state). Can somebody write the energy balance equation for this case?
 
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The specimen A diffuses from the side of the membrane with the concentration cA (side 1) to the other side (side 2) and specimen B diffuses in the opposite direction. Because the temperature at the side 1 is TA and the temperature at the side 2 is TB is heat flux in both directions:
mA*(hA(TA)-hA(TB))
mB*(hB(TB)-hB(TA))

mA, mB - diffusion flux of specimen A/B
hA(TA) - specific enthalpy of specimen A at TA
hA(TB) - specific enthalpy of specimen B at TB
 
Is that correct?
 

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