A 2.0-microfarad capacitor is charged to 250 V. It is then connected to an uncharged 1.0 microfarad capacitor through a 2.2 ohm resistor, by closing switch S in the figure .
Find the total energy dissipated in the resistor as the circuit comes to equilibrium. Hint: Think about charge conservation.
Express your answer using two significant figures.
The answer to the question is 21 millijoule.
Capacitators in series carry the same charge.
U=1/2 * Q * V^2 (energy stored in a capacitor)
The Attempt at a Solution
I don't really know what to do. I guess charge moves from the charged capacitor to the uncharged one, until the both charges on the capacitors are equal. Moving charge is a current, and this current should give an energy dissipation in the resistor.
I tried some calculations on paper, but there's not much use writing them here, since I seem to need help with the basic approach of this problem.
Thanks in advance,