1. The problem statement, all variables and given/known data A 2.0-microfarad capacitor is charged to 250 V. It is then connected to an uncharged 1.0 microfarad capacitor through a 2.2 ohm resistor, by closing switch S in the figure . Find the total energy dissipated in the resistor as the circuit comes to equilibrium. Hint: Think about charge conservation. Express your answer using two significant figures. The answer to the question is 21 millijoule. 2. Relevant equations C=Q/V Capacitators in series carry the same charge. P=I*V I=V/R P=I^2*R U=1/2 * Q * V^2 (energy stored in a capacitor) 3. The attempt at a solution I don't really know what to do. I guess charge moves from the charged capacitor to the uncharged one, until the both charges on the capacitors are equal. Moving charge is a current, and this current should give an energy dissipation in the resistor. I tried some calculations on paper, but there's not much use writing them here, since I seem to need help with the basic approach of this problem. Thanks in advance, Merlione.