Energy distribution plot of neutrinos in beta decay

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SUMMARY

The discussion focuses on the energy distribution plot of neutrinos in beta decay, specifically how to derive the anti-neutrino spectrum from the beta particle spectrum. It is established that the anti-neutrino energy can be approximated by subtracting the beta energy spectrum from the total energy of the beta decay, denoted as Eβ. The most probable energy of the beta particle is approximately Eβ/3, leading to an anti-neutrino energy of about 2/3 Eβ. The resulting anti-neutrino spectrum is continuous and complementary to the beta decay spectrum.

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  • Knowledge of energy spectrum analysis
  • Basic proficiency in plotting functions and interpreting graphs
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Physicists, nuclear engineers, and students studying particle physics or nuclear decay processes will benefit from this discussion, particularly those interested in the energy dynamics of beta decay and neutrino behavior.

Phys pilot
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TL;DR
what's the shape and how I get the spectrum of the kinetic energy of the neutrinos?
Thanks
Hello,
When you have a beta decay you get the typical continuos spectrum representing counts against the kinetic energy of the electron. But what's the shape and how I get the spectrum of the kinetic energy of the neutrinos?
Thanks
 
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It's a 3 body problem, since there is a nucleus, an electron (beta particle) and an anti-neutrino. Given that the nucleus is massive, A * ~931.49 MeV, the beta and anti-neutrino will get most of the energy.

One can approximate the shape of the anti-neutrino spectrum by assuming the total energy of the beta decay, e.g., Eβ, and subtracting the beta energy spectrum. The anti-neutrino energy is approximately the total energy minus the beta energy. The most probably energy of a beta particle in the decay is about Eβ/3, and corresponding anti-neutrino energy would be ~2/3 Eβ.
 
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Astronuc said:
It's a 3 body problem, since there is a nucleus, an electron (beta particle) and an anti-neutrino. Given that the nucleus is massive, A * ~931.49 MeV, the beta and anti-neutrino will get most of the energy.

One can approximate the shape of the anti-neutrino spectrum by assuming the total energy of the beta decay, e.g., Eβ, and subtracting the beta energy spectrum. The anti-neutrino energy is approximately the total energy minus the beta energy. The most probably energy of a beta particle in the decay is about Eβ/3, and corresponding anti-neutrino energy would be ~2/3 Eβ.
I see, so the spectrum would be also continuos and a similar shape?
Thanks
 
Phys pilot said:
I see, so the spectrum would be also continuos and a similar shape?
Thanks
No, the shape for the neutrino would be continuous but complementary to the spectrum of the beta decay, so if the proportion of energy for the beta particle was given by f(E), then the function describing the anti-neutrino energy would be 1-f(E).

See this spectrum for beta particles - http://hyperphysics.phy-astr.gsu.edu/hbase/Nuclear/beta2.html

Draw a horizontal line across the top. The difference between the horizontal line and the curve for the beta particle intensity is approximately the anit-neutrino intensity. Plot the difference vs energy, and that is the anti-neutrino spectrum.
 
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Astronuc said:
Draw a horizontal line across the top. The difference between the horizontal line and the curve for the beta particle intensity is approximately the anit-neutrino intensity. Plot the difference vs energy, and that is the anti-neutrino spectrum.
Huh? The difference between intensity at a given energy and the peak intensity isn't relevant.
If we neglect the recoil of the nucleus then the sum of electron and neutrino energy is constant, so you need to flip the graph across the vertical axis. The largest electron energy corresponds to the smallest neutrino energy and vice versa.
 
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