I Energy distribution plot of neutrinos in beta decay

Click For Summary
In beta decay, the energy distribution of neutrinos can be approximated by considering the total energy of the decay and subtracting the beta particle's energy spectrum. The anti-neutrino spectrum is continuous and complementary to the beta particle spectrum, meaning if the beta particle has a certain energy distribution, the neutrino distribution will reflect the remaining energy. The most probable energy for the beta particle is about Eβ/3, leading to the anti-neutrino having approximately 2/3 Eβ. To visualize this, one can plot the difference between the total energy line and the beta particle intensity curve to derive the anti-neutrino spectrum. Understanding this relationship is crucial for accurately modeling the energy distributions in beta decay processes.
Phys pilot
Messages
28
Reaction score
0
TL;DR
what's the shape and how I get the spectrum of the kinetic energy of the neutrinos?
Thanks
Hello,
When you have a beta decay you get the typical continuos spectrum representing counts against the kinetic energy of the electron. But what's the shape and how I get the spectrum of the kinetic energy of the neutrinos?
Thanks
 
Physics news on Phys.org
It's a 3 body problem, since there is a nucleus, an electron (beta particle) and an anti-neutrino. Given that the nucleus is massive, A * ~931.49 MeV, the beta and anti-neutrino will get most of the energy.

One can approximate the shape of the anti-neutrino spectrum by assuming the total energy of the beta decay, e.g., Eβ, and subtracting the beta energy spectrum. The anti-neutrino energy is approximately the total energy minus the beta energy. The most probably energy of a beta particle in the decay is about Eβ/3, and corresponding anti-neutrino energy would be ~2/3 Eβ.
 
  • Like
Likes vanhees71 and Phys pilot
Astronuc said:
It's a 3 body problem, since there is a nucleus, an electron (beta particle) and an anti-neutrino. Given that the nucleus is massive, A * ~931.49 MeV, the beta and anti-neutrino will get most of the energy.

One can approximate the shape of the anti-neutrino spectrum by assuming the total energy of the beta decay, e.g., Eβ, and subtracting the beta energy spectrum. The anti-neutrino energy is approximately the total energy minus the beta energy. The most probably energy of a beta particle in the decay is about Eβ/3, and corresponding anti-neutrino energy would be ~2/3 Eβ.
I see, so the spectrum would be also continuos and a similar shape?
Thanks
 
Phys pilot said:
I see, so the spectrum would be also continuos and a similar shape?
Thanks
No, the shape for the neutrino would be continuous but complementary to the spectrum of the beta decay, so if the proportion of energy for the beta particle was given by f(E), then the function describing the anti-neutrino energy would be 1-f(E).

See this spectrum for beta particles - http://hyperphysics.phy-astr.gsu.edu/hbase/Nuclear/beta2.html

Draw a horizontal line across the top. The difference between the horizontal line and the curve for the beta particle intensity is approximately the anit-neutrino intensity. Plot the difference vs energy, and that is the anti-neutrino spectrum.
 
Astronuc said:
Draw a horizontal line across the top. The difference between the horizontal line and the curve for the beta particle intensity is approximately the anit-neutrino intensity. Plot the difference vs energy, and that is the anti-neutrino spectrum.
Huh? The difference between intensity at a given energy and the peak intensity isn't relevant.
If we neglect the recoil of the nucleus then the sum of electron and neutrino energy is constant, so you need to flip the graph across the vertical axis. The largest electron energy corresponds to the smallest neutrino energy and vice versa.
 
  • Like
Likes vanhees71 and Astronuc
Thread 'Some confusion with the Binding Energy graph of atoms'
My question is about the following graph: I keep on reading that fusing atoms up until Fe-56 doesn’t cost energy and only releases binding energy. However, I understood that fusing atoms also require energy to overcome the positive charges of the protons. Where does that energy go after fusion? Does it go into the mass of the newly fused atom, escape as heat or is the released binding energy shown in the graph actually the net energy after subtracting the required fusion energy? I...