- #1

mathological

- 10

- 0

ok so everytime I think that I have understood the concept of Energy transmission, losses and voltage drop, I get even more confused about things.

I have searched several threads on this forum and the physics forum but failed to find anything that directly answers my query. So I kindly request your help on the fundamental concept.

I will try to give an example and I would like you guys to correct me where I am wrong -- Thanks in advance!!!

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If a 1 MW load is to be supplied by a 10kV feeder, and the cable resistance is 1 ohms, then the current drawn by the load (or the current travelling on the cable) is:

I = P/V = 100 A

The line losses are I^2*R = 10 kW and the Voltage Drop = I*R = 100 V

Is it right to say that:

a) Voltage at supply point is 10kV

b) Voltage at consumer end is 9.9kV (10kV - 100V)

c) The current through the cable is 100A

d) The power required is 1 MW but the actual power being delivered is 0.99 MW [ (P - losses) OR (V*I = 9.9kV * 100A) ]

e) hence the efficiency of this system is 0.99MW/1MW * 100 = 99% efficient?

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Please correct me where I am wrong.

Thank you.