Energy-Momentum tensor components for complex Klein-Gorden field

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SUMMARY

The discussion centers on the components of the energy-momentum tensor for the complex Klein-Gordon field, specifically the expression T^{\mu\nu}=(\partial^{\mu}\phi)^{\dagger}(\partial^{\nu}\phi)+(\partial^{\mu}\phi)(\partial^{\nu}\phi^{\dagger})-\mathcal{L}g^{\mu\nu}. The participant clarifies that T^{0i} is derived as T^{0i}=-[(\partial_{t}\phi)^{\dagger}\nabla^{i}\phi+(\partial_{t}\phi)\nabla^{i}\phi^{\dagger}]. They confirm that the Lagrangian density term drops out due to the diagonal nature of the metric tensor g^{\mu\nu}, which results in off-diagonal elements being zero.

PREREQUISITES
  • Understanding of the complex Klein-Gordon field
  • Familiarity with the energy-momentum tensor formulation
  • Knowledge of Lagrangian density in field theory
  • Basic concepts of tensor calculus and metric tensors
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  • Study the derivation of the energy-momentum tensor in quantum field theory
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  • Learn about the properties of diagonal and off-diagonal components of metric tensors
  • Investigate the relationship between time and spatial derivatives in field equations
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The discussion is beneficial for theoretical physicists, students of quantum field theory, and researchers focusing on the properties of the Klein-Gordon field and energy-momentum tensors.

Dixanadu
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Hey guys,

So I have the stress energy tensor written as follows in my notes for the complex Klein-Gordon field:

T^{\mu\nu}=(\partial^{\mu}\phi)^{\dagger}(\partial^{\nu}\phi)+(\partial^{\mu}\phi)(\partial^{\nu}\phi^{\dagger})-\mathcal{L}g^{\mu\nu}

Then I have the next statement that T^{0i} is given by

T^{0i}=-[(\partial_{t}\phi)^{\dagger}\nabla^{i}\phi+(\partial_{t}\phi)\nabla^{i}\phi^{\dagger}]

And I was wondering how this comes about. I can sort of see what's happened here. Obviously you replace mu and nu with 0 and i respectively to split the spatial and time derivatives. However I have a couple of questions:

1) is it true that \partial^{t}\phi=-\partial_{t}\phi?
2) why does the Lagrangian density at the end, \mathcal{L}g^{\mu\nu} drop out?

Thanks a lot guys :)
 
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Okay maybe I know why the Lagrangian density drops out...is it cos g^{\mu\nu} is diagonal and so g^{0i}, for i = 1, 2, 3, are off-diagonal elements which are 0?
 

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