Energy Needed To Go A Given Speed

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Discussion Overview

The discussion centers on the energy required to accelerate a given mass to a specific speed, particularly at relativistic speeds approaching the speed of light. Participants explore the relevant equations and concepts related to kinetic energy in both classical and relativistic contexts.

Discussion Character

  • Technical explanation, Mathematical reasoning

Main Points Raised

  • One participant inquires about the equation for calculating the energy needed to accelerate a mass to a given speed, specifically mentioning a mass of 1 gram at half the speed of light.
  • Another participant suggests using the classical kinetic energy formula KE = ½mv² for low speeds, but notes that the calculation becomes more complex at higher speeds.
  • A different participant provides the relativistic energy formula, stating that the energy of a mass at speed v is mc²/√(1 - v²/c²) joules, and explains how to derive the kinetic energy from this expression.
  • One participant seeks confirmation on their calculation, suggesting that it would take approximately 9e+12 kilojoules for a mass of 20 kilograms to reach 0.1c, and another participant agrees with this estimate.

Areas of Agreement / Disagreement

Participants generally agree on the use of relativistic equations for calculating energy at high speeds, but there is no consensus on the specific calculations or values presented, as some participants are still seeking confirmation of their understanding.

Contextual Notes

The discussion does not resolve the complexities involved in applying the relativistic energy formula, and assumptions regarding the conditions of the calculations are not fully articulated.

Sothh
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Hey, I don't have much of a physics background.

I have been searching for an equation that shows how much energy is needed to make a given mass go a given speed.

For example, let's say I want to send 1 gram at half light speed. How much energy is required?

Thanks!
 
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Sounds like you want to calculate the kinetic energy of the mass.

For low speeds (compared to the speed of light) the kinetic energy is KE = ½mv². But for fast speeds, it's a bit more complicated:
76cc95f8c7e7d0edde43428308072182.png


(I can't seem to get Latex to work.)
 
Welcome to PF!

Hi Sothh! Welcome to PF! :smile:

For a speed of v metres per second, the energy of a mass of m kilograms is mc2/√(1 - v2/c2) joules.

If v = 0 (the mass is at rest), that energy is obviously just mc2, which is therefore called the rest-mass.

So the extra energy needed to get it to speed v (the kinetic energy) is mc2(1/√(1 - v2/c2) - 1) joules. :wink:

If v/c is very small, then that extra (kinetic) energy is approximately mc2(v2/2c2), ie mv2/2.
 
Thanks!

Just to confirm I am using this correctly, it should take 20 kilograms around 9e+12 kilojoules to go .1c, correct?
 
Sothh said:
Just to confirm I am using this correctly, it should take 20 kilograms around 9e+12 kilojoules to go .1c, correct?
Sounds about right.
 

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