Energy required to strip final electron

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SUMMARY

The energy required to remove the final electron from a doubly ionized lithium (Li2+) atom can be calculated using the formula En = -z^2/n^2. For Li2+, the atomic number z is 3, and since there is one remaining electron, n is 1. Therefore, the energy required is En = -3^2/1^2 = -9 eV. This indicates that 9 eV of energy is needed to strip the final electron from the Li2+ atom.

PREREQUISITES
  • Understanding of atomic structure and ionization energy
  • Familiarity with the formula En = -z^2/n^2
  • Knowledge of electron-volts as a unit of energy
  • Basic concepts of hydrogen-like atoms
NEXT STEPS
  • Study the properties of hydrogen-like atoms and their energy levels
  • Learn about the ionization energies of different elements
  • Explore the concept of electron transitions in quantum mechanics
  • Investigate the implications of ionization energy in chemical reactions
USEFUL FOR

Students studying atomic physics, educators teaching quantum mechanics, and anyone interested in the behavior of ionized atoms and their energy requirements.

BobMcPhysics
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Homework Statement



Find the energy in electron-volts required to remove the remaining electron from a doubly ionized lithium (Li2+) atom.

Homework Equations



En=-z^2/n^2

The Attempt at a Solution



I thought z was 3 for lithium, that doesn't work. I thought since there was only one remaining electron you could treat it like Hydrogen and use z (or E1) = -13.6 eV but that's not right either. Clearly the n in the denominator is 1 from above.

I'm lost!
 
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