1. The problem statement, all variables and given/known data Energy in the circuit remains constant. When the current is flowing, the energy stored is all stored in the inductor. When the current stops flowing, it is because all the energy is stored in the capacitor. Find the fraction of energy stored in the inductor when half of the max charge is on the capacitor. L = inductor C = capacitor I = current 2. Relevant equations 1/2 *Q^2/C = U of capacitor 1/2 * LI^2 = U of inductor 3. The attempt at a solution Didn't know where to really go. 1/2 *Q^2/C + 1/2 * LI^2 = U Q= .5Q 1/8Q^2/C + x*LI^2 =U x= 7/8?