Engineering Mechanics Couple system question

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SUMMARY

The discussion focuses on converting a 25-lb force acting on a socket wrench's handle into an equivalent force-couple system at the origin O of a coordinate system. The force is applied at an angle of 20 degrees from the -z-axis and the handle AB is positioned at 30 degrees off the x-axis. Participants clarify that the goal is to determine a force and moment at point O that replicate the effects of the original force at the handle's end. Calculated results include a moment M = 196.94i + 352.35j - 128.25k and a force F = -8.55j + 23.49k.

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Taiki_Kazuma
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what is this problem searching for?

A 25-lb force acting in a vertical plane parallel to the yz plane is applied to the 8-in.-long horizontal handle AB of a socket wrench. Replace the force with an equivalent force-couple system at the origin O of the coordinate system.


See attached pic of the problem.

AO is 15-in.-long vertical

AB is 30 degrees off the x-axis

Force(in red) is 25-lb and is 20 degrees from the -z-axis

-------------------------------------------------------------

ok tell me if I"m wrong.

I think this problem is looking for the force that should be applied to cancel the other force but still have the same moment about O.

Please tell me if I'm thinking correctly...

however, how should I go about doing that? if that is the solution to this problem.
 

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Taiki_Kazuma said:
A 25-lb force acting in a vertical plane parallel to the yz plane is applied to the 8-in.-long horizontal handle AB of a socket wrench. Replace the force with an equivalent force-couple system at the origin O of the coordinate system.

I think this problem is looking for the force that should be applied to cancel the other force but still have the same moment about O.

Not exactly. What you need to do is come up with a force and moment that, when applied at the point O, are equivilent to the lone force acting at the end of the handle.
 
ok, I think I get it...please correct me if I'm wrong (and let me know if I'm right)...


First I add vectors that are equal to F and -F at point O.

then I find the couple produced by F (original force) and -F. That will give me the answer of the couple moment at point O. and then I have F applied at O left over.

Is that what it is looking for?

I calculated the following answers:

M = 196.94i + 352.35j - 128.25k

F = -8.55j + 23.49k
 
Last edited:
Taiki, you only need to calculate the moment of F with respect to the origin, and put the rectangular representation of F. That should give you your Force-couple system at O.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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