Understanding Forces and Motion in a 3D Coordinate System

In summary, the toy rocket engine is securely fastened to a large puck that can glide with negligible friction over a horizontal surface. The 4.00-kg puck has a velocity of 3.00ˆi ms at one instant. Eight seconds later, its velocity is (8.00ˆi + 10.0ˆj) ms. Assuming the rocket engine exerts a constant horizontal force, find (a) the components of the force and (b) its magnitude.
  • #1
Const@ntine
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Homework Statement



A toy rocket engine is securely fastened to a large puck that can glide with negligible friction over a horizontal surface, taken as the xy plane. The 4.00-kg puck has a velocity of 3.00ˆi ms at one instant. Eight seconds later, its velocity is (8.00ˆi + 10.0ˆj) ms. Assuming the rocket engine exerts a constant horizontal force, find (a) the components of the force and (b) its magnitude.

Homework Equations



ΣF = m*a
a = ΔV/Δt

The Attempt at a Solution



Well, I took the all the info and applied it on the various formulas I know, and found the correct results, according to the book. So my problem doesn't lie there, as it's a simple problem of putting the correct quantities in the correct "positions". My problem lies more with "conceptualizing" the problem.

I also checked the manual, but I can't understand one thing: It says that the force that the engine exerts on the puck is horizontal, so I take it that means the X part of the XY axis', correct? So, if this force is horizontal, then how can he ask me about its component of the net force? Does the statement mean that it's not horizontal per se, just that it acts on the first quadrant? Apart from that, how does the puck develop a velocity at the Y/vertical plane?

From what I understand from the statement, it's a standard round puck on top of a, say floor, and I've put an engine on the back, that exerts a horizontal F force on it, causing it to move horizontally, but it somehow develops a velocity at both planes. Could anyone explain to me what exactly I'm missing?

Thanks!
 
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  • #2
Darthkostis said:
I also checked the manual, but I can't understand one thing: It says that the force that the engine exerts on the puck is horizontal, so I take it that means the X part of the XY axis', correct? So, if this force is horizontal, then how can he ask me about its component of the net force? Does the statement mean that it's not horizontal per se, just that it acts on the first quadrant? Apart from that, how does the puck develop a velocity at the Y/vertical plane?
In this case the Y-axis is not vertical. The entire XY plane is horizontal. If a vertical direction were involved it would (likely) be designated Z.
 
  • #3
gneill said:
In this case the Y-axis is not vertical. The entire XY plane is horizontal. If a vertical direction were involved it would (likely) be designated Z.

Ah, so it's as if I'm dealing with 3D object that slides on the ground. And the problem is using the X & Z axis' of the usual XYZ axis, just renaming the Z one Y. So technically, it's moving horizontally, but not in a straight line, it skews a bit to the side. Correct?
 
  • #4
You've got the picture. The XY plane is generally taken to be horizontal when using a 3D XYZ coordinate system. Z is the usual designation for the vertical direction. X, Y, and Z are really just labels that we have come to use by convention.

We often use a 2D coordinate system to analyze motions that occur in a plane, such as typical projectile motion, and then we usually assign the X to the horizontal direction and Y to the vertical direction. But this is not strictly necessary. All those projectile motion equations could be written using X and Z instead of X and Y. Or, other letters or symbols could be assigned (UVW, for example). It's really just a matter of convention.
 
  • #5
gneill said:
You've got the picture. The XY plane is generally taken to be horizontal when using a 3D XYZ coordinate system. Z is the usual designation for the vertical direction. X, Y, and Z are really just labels that we have come to use by convention.

We often use a 2D coordinate system to analyze motions that occur in a plane, such as typical projectile motion, and then we usually assign the X to the horizontal direction and Y to the vertical direction. But this is not strictly necessary. All those projectile motion equations could be written using X and Z instead of X and Y. Or, other letters or symbols could be assigned (UVW, for example). It's really just a matter of convention.

Got it. Yeah, I know the letters are interchangable, but I've not tackled 3D problems yet, so when I saw "horizontal" my mind went straight to the usual "X is horizontal, Y is vertical" concept.

Thanks for clearing this up for me!
 

1. How does a rocket engine push a puck?

A rocket engine works by combusting fuel and oxidizer to produce hot gases, which are then expelled out of the engine at high speeds. This creates a reaction force in the opposite direction, pushing the rocket (or in this case, the puck) forward.

2. Why is a rocket engine necessary to push a puck?

A rocket engine is necessary because it provides a large amount of thrust, or force, in a short amount of time. This allows the puck to accelerate quickly and achieve high speeds, which is necessary for space travel.

3. How does the size of a rocket engine affect the speed of the puck?

The size of a rocket engine directly affects the amount of thrust it can produce. A larger engine can produce more thrust, which can push the puck to higher speeds. However, the size of the engine also affects the weight of the rocket, so there is a balance between thrust and weight that must be considered.

4. Can a rocket engine push a puck indefinitely?

No, a rocket engine cannot push a puck indefinitely. Rocket engines require fuel and oxidizer to produce thrust, so once these resources are depleted, the engine will stop working. In space, where there is no air resistance, a rocket engine can theoretically continue pushing a puck until it reaches its destination or runs out of fuel.

5. How is the efficiency of a rocket engine measured?

The efficiency of a rocket engine is typically measured by its specific impulse, which is the amount of thrust produced per unit of fuel. A higher specific impulse indicates a more efficient engine, as it can produce more thrust with less fuel consumption.

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