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Line of action for which the resultant force of the wrench passes

  1. Sep 30, 2014 #1

    imd

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    phprAb3vu.png





    In tightening a bolt whose center is at point O, a person exerts a 180-N force on the ratchet handle with his right hand. In addition, with his left hand he exerts a 90-N force as shown in order to secure the socket onto the bolt head. Determine the equivalent force–couple system at O. Then find the point in the x-y plane through which the line of action of the resultant force of the wrench passes.

    The answer should be:

    R = -90j - 180k N

    M = -6.3i - 36j N*m
    x = -160 mm

    y = 35 mm
     
  2. jcsd
  3. Oct 1, 2014 #2

    BvU

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    And what is your question ?
     
  4. Oct 2, 2014 #3

    imd

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    Sorry I did not specify. I am not sure how to solve the problem, I can find the Force and Moment around O but cannot find the line of action on x. If you could briefly explain how to do the problem that would be great. Thanks!
     
  5. Oct 3, 2014 #4

    BvU

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    Ah, that clears some of the fog. Next time use the template (read the guidelines to find out why it's compulsory in PF).
    And: welcome to PF :) !

    Not exactly as described in the guidelines, but I can now at least estimate you are able to sort out what is given and you can convert at least some of what is asked into something to do. I hope that's also true if the answer isn't in the back of the book.

    Now comes the bummer: I have no idea either where the -160 comes from ! Resultant force link doesn't help me: there is nothing in the x or -x direction I can find. Almost want to ask: could this be a typo ?

    But perhaps someone else listening in has a better idea ?
     
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