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No, I meant what I said. You have a qubit (the physical realisation is not important, but if you like you can think of it as polarization of photons), and you can measure in both basis.DrChinese said:If you have a |V> photon stream (say from a laser) that you can only measure on the ##\{|+\rangle, |-\rangle\}## basis, yes, that is meaningful.
Yes, it is exactly the same as in Ma's paper, just a simpler case, no swapping involved, so that the trees are not in the way to see the woods. And, yes, I disagree. On this you are wrong! It is very basic, your confusion is not even in the basic QM. It is much simpler it is writing the same vector in two different basis. But all this has been said many times. It is your job to clear this for yourself. Untill then you will not understand Ma's paper.DrChinese said:I would not call them the same state though. Naturally, I can distinguish them experimentally using a suitably oriented PBS.
Similarly, I can distinguish the difference between Ma's (1) and (2) experimentally. As they do. Megidish as well. Disagree?