Enthelpy change for an ideal gas

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Homework Help Overview

The discussion revolves around the enthalpy change equation for an ideal gas, specifically ΔH = ΔU + (Δn)RT. Participants are exploring the implications of temperature being constant and how it affects the internal energy change (ΔU) and the number of moles (Δn).

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the application of the equation under constant temperature conditions, particularly the treatment of ΔU and whether to use initial or final temperature. There is also discussion about the implications of changing the number of moles and how it affects the overall equation.

Discussion Status

The discussion is active, with participants providing insights and corrections regarding the equation. Some have suggested that ΔU could be zero under certain conditions, while others are clarifying the relationship between internal energy, temperature, and the number of moles. There is recognition of the complexity involved in applying the equation correctly.

Contextual Notes

Participants note that the equation is derived under the assumption of constant temperature and pressure, which raises questions about the validity of ΔU in scenarios where the number of moles changes.

babita
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Homework Statement



I'm not able to understand the following equation
ΔH = ΔU + (Δn)RT
firstly if T is taken to be constant (as the book says), ΔU = 0
if T is not constant then which T i am supposed to put in? initial or final?

Homework Equations


please help. Thank you.


The Attempt at a Solution

 
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babita said:

Homework Statement



I'm not able to understand the following equation
ΔH = ΔU + (Δn)RT
firstly if T is taken to be constant (as the book says), ΔU = 0
if T is not constant then which T i am supposed to put in? initial or final?

Homework Equations


please help. Thank you.

The Attempt at a Solution


Hi babita! :smile:

Looks to me that your equation is not right.
I think it should be:
ΔH = ΔU + Δ(nRT)

Assuming n is constant, this is the same as:
ΔH = ΔU + nRΔT

Does that answer your question?
To give a more extensive explanation:

H is defined as H=U+PV.
With the ideal gas law PV=nRT, it follows that H=U+nRT.
For a change in H we get:
ΔH=Δ(U+nRT)=ΔU+Δ(nRT)
 
hi:smile:
yeah that would have made sense but its written "at constant temperature" every where :'(
 
Okay, so apparently the amount of matter does not stay constant and you have a Δn.

If the temperature is constant then the initial temperature is the same as the final temperature.

Your equation becomes:
ΔH=ΔU+Δ(nRT)=ΔU+(Δn)RT.

And as you surmised, with T constant, you have ΔU=0, so you get:
ΔH=(Δn)RT
 
I like Serena said:
Okay, so apparently the amount of matter does not stay constant and you have a Δn.
amount of matter may or may not change...Δn means no of moles of gaseous products minus no of moles of gaseous reactants

THAT is my confusion...at constant T , ΔU makes no sense
 
Actually, in retrospect ΔU does make sense if the number of moles changes.
My bad.

For an ideal gas you have: U=n Cv T
With constant T, the change in U is:
ΔU=(Δn) Cv T
 
Cv is heat capacity at constant volume...i don't think volume is constant here...in my book the equation have been derived assuming constant T & P.
 
Also Internal energy of an ideal gas is directly proportional to T
 
Cv is indeed the heat capacity at constant volume.

However, it turns out that the formula U=n Cv T holds for an ideal gas, even if the volume is not constant.

That's not really relevant here though.
As you said internal energy U is directly proportional to T.
U is also directly proportional to the number of moles n.
 
  • #10
I like Serena said:
Cv is indeed the heat capacity at constant volume.

However, it turns out that the formula U=n Cv T holds for an ideal gas, even if the volume is not constant.

.

yeah sry ...that was silly
 
  • #11
and yes U is proportional to n, equation makes sense at constant T ...missed that point... thanks :)
 
  • #12
You're welcome. :)
 

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