Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Entropy change in a reversible isothermal process

  1. Feb 25, 2016 #1
    Why does ∆S = 0 for a reversible process, but for a reversible isothermal process, ∆S is given by nRln(Vf/Vi) (or other variations of that equation)?
  2. jcsd
  3. Feb 25, 2016 #2
    You are confusing ΔS for the system with ΔS for the combination of system and surroundings.
  4. Feb 25, 2016 #3
    Chestermiller is correct.

    ∆S(system) = nRln(Vf/Vi)

    ∆S(total)= ∆S(surroundings) + ∆S(system) = 0
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook