Sylvia
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Why does ∆S = 0 for a reversible process, but for a reversible isothermal process, ∆S is given by nRln(Vf/Vi) (or other variations of that equation)?
Entropy change in a reversible isothermal process
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You are confusing ΔS for the system with ΔS for the combination of system and surroundings.
Jeff Armstrong
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Chestermiller is correct.∆S(system) = nRln(Vf/Vi)
∆S(total)= ∆S(surroundings) + ∆S(system) = 0
∆S(total)= ∆S(surroundings) + ∆S(system) = 0
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