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Entropy change in a reversible isothermal process

  1. Feb 25, 2016 #1
    Why does ∆S = 0 for a reversible process, but for a reversible isothermal process, ∆S is given by nRln(Vf/Vi) (or other variations of that equation)?
     
  2. jcsd
  3. Feb 25, 2016 #2
    You are confusing ΔS for the system with ΔS for the combination of system and surroundings.
     
  4. Feb 25, 2016 #3
    Chestermiller is correct.


    ∆S(system) = nRln(Vf/Vi)

    ∆S(total)= ∆S(surroundings) + ∆S(system) = 0
     
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