Entropy Equatio for a closed system

[Crazy Tosser]

I must have already been banned for spamming threads.

But oh well.

You know how change in entropy dS of a closed system assuming reversibility of the processes = (\frac{dQ}{T})_{rev}=\frac{C_{p}dT}{T}

So when you try to find the actual entropy with respect to temperature, it's:

\displaystyle \int S_{T} = S_{0} + \int^{T}_{0} \C_{p}dT/T\

That's understandable. But that's my derivation. The text uses a slightly different formula:

S_{T} = S_{0} + \int^{T}_{0} \\frac{C_{p}dT}{T}\ + \sum \frac{\Delta H_{trans}}{T}

So my question 1 is: where did the \sum \frac{\Delta H_{trans}}{T} come from?

And my question 2 is:
if we say that heat capacity C_{p} is constant (it's not strictly constant, but with an approximation, we can call it a constant), we have:

\int \frac{C_{P}dT}{T} \sim C_{P} \int \frac{dT}{T}=
\sim C_{P} \ln{T}

Could the top eqn. be used as an approximation (part of an approximation, this is only a part of the equation)

As you can tell I am not that well-versed in Latex D=

Thanks

~Tosser

 

[Chestermiller]

The $\Delta H/T$ terms come from the phase transitions from solid-to-liquid and from liquid-to-vapor (and any other phase transitions that occur, as, for example, from different crystal forms).