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Entropy of the distribution as a function of time

  1. Nov 12, 2015 #1
    I am having an issue with finding the entropy in my program. I was asked to the find the entropy of the distribution as a function of time but i do not know where to start with entropy.

    I understand entropy but putting it in my program is where I am stuck

    Here is my code:

    Code (Python):
    # -*- coding: utf-8 -*-
    Created on Thu Nov 12 11:15:44 2015


    import matplotlib.pyplot as plt

    import random

    def Function(D):    #D = dimensions
        sumOfSquare = 0.0
        for i in range(0, len(D)):
            sumOfSquare += D[i]**2
        if sumOfSquare <=1:
            return 1
            return 0
    def MonteCarlo(f_n,dim):
        intervalsForSphere = 1000000
        integral = 0.0
        for i in range(0, intervalsForSphere):
            for j in range(0,len(dim)):
                dim[j] = random.random()
            integral += f_n(dim)
        integral = (1-(-1))**len(dim)/intervalsForSphere * integral
        return integral
    print("10 dimensional unit circle ")
    Ten_Dim= list(range(1,10+1))
    ten_D_circle = MonteCarlo(Function,Ten_Dim)

    AreaofCircle = []
    x = []

    for i in range(1,13):
        D = list(range(1,i+1))
        AreaofCircle.append(MonteCarlo(Function, D))

    plt.title("Area of N-dimensional Unit Circle")

  2. jcsd
  3. Nov 12, 2015 #2
    Not really about entropy, but are you certain about this expression? It is always evaluated to 2 between the parentheses. Shouldn't it be (1 - (-1)**len(dim)…) or something similar? I'll look further into the code and try to help, but the quoted code above made me scratch my head.
  4. Nov 12, 2015 #3


    Staff: Mentor

    In addition to what DevacDave said about (1 - (-1)) always evaluating to 2, the expression after '**' probably isn't what you want.
    The ** operator is higher in precedence than any of the arithmetic operators, so the expression on the right above is raising 2 to the power len(dim), and is then dividing that result by intervalsForSphere, and finally, multiplying by integral.
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