Entropy of the river due to coal heating

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SUMMARY

The discussion focuses on calculating the gamma (Cp/Cv) ratio for an ideal gas after adding 980 J of heat to 1.75 moles, raising the temperature from 10.0°C to 25.0°C at constant pressure. The gas performs 234 J of work during expansion. The relevant equations include Cv = Cp - nR and Gamma = Cp/Cv. To solve for gamma, one must apply the first law of thermodynamics, considering the change in internal energy (ΔU) and its relationship with Cv and the change in temperature (ΔT).

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Gamma (Cp/Cv) of a gas

Homework Statement



An experimenter adds 980 J of heat to 1.75 mols of an ideal gas to heat it from 10.0 C to 25.0 C at constant pressure. The gas does 234 J of work during the expansion. Calculate gamma (Cp/Cv) for the gas.

Homework Equations



Cv=Cp-nR
Gamma =Cp/Cv

The Attempt at a Solution



No idea where to start. I found other ratios between the variables but I'm still confused. Do i have to use Q or delta Q?
 
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idkididk said:

Homework Statement



An experimenter adds 980 J of heat to 1.75 mols of an ideal gas to heat it from 10.0 C to 25.0 C at constant pressure. The gas does 234 J of work during the expansion. Calculate gamma (Cp/Cv) for the gas.

Homework Equations



Cv=Cp-nR
Gamma =Cp/Cv

The Attempt at a Solution



No idea where to start. I found other ratios between the variables but I'm still confused. Do i have to use Q or delta Q?
Apply the first law. Assume that it is a quasi-static process. What is ΔU? How does ΔU relate to Cv and ΔT? What is the difference between Cv and Cp? Answer all those questions and you will be able to determine Cp.

AM
 

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