- #1
elemis
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The above equation gives the EPE of two point charges separated by a distance r.
Firstly, I do not understand how this formula gives the TOTAL EPE of the system.
Secondly, let's say I have three deuterium nuclei moving towards one another with initial speed V.
They all stop instantaneously at the same point such that they are all separated from one another by distance r.
How would the above formula change to give the total EPE of the system ? Would you consider each pair of nuclei ?
So total EPE of system = (EPE of 1st+2nd) + (1st+3rd) + (2nd+3rd) ?
Hence, the formula becomes
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