Epsilon-Delta Proof Homework: Understanding the Thought Process

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Homework Statement



For every ε> 0, there is a δ> 0 such that 1- δ< x <1 + implies 2- ε <7-5x <2 + ε


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The Attempt at a Solution



My understanding of epsilon-delta proofs is very minimal at this point. Was hoping someone would be able to explain your thought process when attempting these kinds of proofs. Thank you!
 
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hi dainty77! :smile:
dainty77 said:
Was hoping someone would be able to explain your thought process when attempting these kinds of proofs.

my thought process would be to attempt the simplest possible solution first …

ie try δ = kε first (for a constant k),

then δ = kε2, then δ = k√ε and so on :wink:
 
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I would start with [itex]2- \epsilon< 7- 5x[/itex] and see that [itex]-5- \epsilon< -5x[/itex] so that [itex]x< 1+ \epsilon/5[/itex] and [itex]x- 1< \epsilon/5[/itex]. Then turn to [itex]7- 5x< 2+ \epsilon[/itex], so that [itex]-5x< -5+ \epsilon[/itex] and [itex]x> 1- \epsilon/5[/itex], [itex]x- 1> -\epsilon/5[/itex]. Now do you see what [itex]\delta[/itex] must be?
 
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tiny-tim said:
hi dainty77! :smile:


my thought process would be to attempt the simplest possible solution first …

ie try δ = kε first (for a constant k),

then δ = kε2, then δ = k√ε and so on :wink:

I see where you are gettiing at! Let me work on it some more. Thank you for your help!
 

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