Equality between centrifugal force and V

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Discussion Overview

The discussion revolves around the equality between centrifugal force and the gradient of potential, specifically the expression mv²/r = |dV/dr|. Participants explore the meanings of the symbols involved and the conditions under which the equality might hold.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Some participants question the validity of the equality mv²/r = |dV/dr|, suggesting that they may not be equal under certain conditions.
  • It is noted that the left side represents centrifugal force, while the right side involves potential V and its gradient.
  • One participant proposes that the equation could be expressed as mv²/r = |dU/dr|, where U represents gravitational or electric potential.
  • Another participant attempts to relate the expression to Newton's second law, suggesting that the terms can be interpreted in terms of force and acceleration.
  • There is a discussion about the educational context, with one participant mentioning that understanding the relationship between potential and force is no longer part of the A-level physics curriculum in the UK.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the equality. Some express uncertainty about its validity, while others provide alternative interpretations or formulations of the relationship.

Contextual Notes

There are limitations regarding the assumptions made about the conditions under which the equality holds, as well as the educational background of participants influencing their understanding of the concepts involved.

soul
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Hi everyone,

Today in a question I saw an equality like this but I couldn't figure out how they are equal? Can anyonu help me please?

mv^2/ r = | dV/dr |
 
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What do the various symbols in this equality represent?
 
I can't figure it out either, probably because they are not equal. If the equation was: m*v^2/r = dv/dr*m then they would be equal.
 
In the left side of the equation is the known centrifugal force. m--mass,v--velocity,r--radius,on the right side V is the potential,r--radius
 
Are you working at a level where you can relate forces to gradients of potential?
 
soul said:
Hi everyone,

Today in a question I saw an equality like this but I couldn't figure out how they are equal? Can anyonu help me please?

mv^2/ r = | dV/dr |

Hi soul! :smile:

Could that be mv^2/ r = | dU/dr |, where U is the gravitational or electric potential?
 
Yes, tiny-tim.it is. I think I am not good enough to express myself. Thank you.
 
Writing mv^2/ r = | dV/dr | is like writing ma=F (which you might be more familiar with?). Does this help?
 
Could you explain it in a more detailed way, please,JimChampion?
 
  • #10
F=ma is a common way of expressing Newton's second law of motion for an object with constant mass m.

The mv^2/ r = | dV/dr | is equivalent to writing ma=F because

v^2/r is the centripetal acceleration

|dV/dr| is the magnitude of the centripetal force (given by the gradient of the potential V)
 
  • #11
I don't really know what level of explanation you're after!

When I did A-level physics (in the UK, 1994) knowing about potential and how it relates to force was part of the course. I now teach A-level physics, and this is no longer part of the course: anything with calculus is avoided and probably wouldn't be encountered unless you studied an undergraduate physics course.
 

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