- #1

SebastianRM

- 39

- 4

g = Ω^2 * R * sinθ * cosθ

So I tried to draw this: using a "big" X-shaped axis where the / component goes along the main gravity direction while \ points normal to / this direction. Then the centrifugal force points out of the center of the X into the x direction, with and angle θ between the y-axis and the / direction. Thus the angle between the centrifugal force and \, should be 90 - θ, and so its projection along that direction should be cos(90-θ).

So i did not arrive to the conclusion of the book, where am I going wrong?

Thank you in advance.