Equation form of a line in 3-D

  • Thread starter yvonnars
  • Start date
  • #1
8
0

Homework Statement



Fine the equation form of the line L that is perpendicular to the plane Q with equation
-x+3y+2z=1 and passing through the origin.

Homework Equations



Parametric form of a line:
L=(0,0,0)+s(-1,3,2)
so x/-1=y/3=z/2

The Attempt at a Solution


x+y+z=4s
but then what is the value of s?
 

Answers and Replies

  • #2
rock.freak667
Homework Helper
6,230
31
s is just a parameter, for different values of s you will get different points on the line.

Remember L is also (x,y,z) so get s in terms of each x,y and z and they will all be equal to one another.
 
  • #3
8
0
s is just a parameter, for different values of s you will get different points on the line.

Remember L is also (x,y,z) so get s in terms of each x,y and z and they will all be equal to one another.

So will the equation form of this line just be x+y+z=4s?
 
  • #4
rock.freak667
Homework Helper
6,230
31
So will the equation form of this line just be x+y+z=4s?

No, from L=(0,0,0)+s(-1,3,2) = (0-s,0+3s,0+2s)

L = (x,y,z) = (0-s,0+3s,0+2s)

x = 0-s and so on. Just make s the subject for each one and then put them all equal to each other.
 

Related Threads on Equation form of a line in 3-D

Replies
2
Views
469
  • Last Post
Replies
4
Views
686
  • Last Post
Replies
8
Views
21K
Replies
9
Views
2K
Replies
3
Views
1K
Replies
3
Views
3K
  • Last Post
Replies
1
Views
661
Replies
5
Views
6K
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
2
Views
7K
Top