Find an equation of the plane that contains the lines given by:
(x-1)/-2 = y - 4 = z and (x-2)/-3 = (y-1)/4 = (z-2)/-1
The Attempt at a Solution
Not too sure about how to go about it. I believe these are the parametric equations for the lines:
x = 1-2t w/ normal vector = (-2,0,0)
x=2-3t w/ normal vector = (-3, 4, -1)
If I take the cross product of those normal vectors, I get (0, -2, -8). What do I do from here or am I going in the wrong direction?