Equation of a plane given point P and a line

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SUMMARY

The discussion focuses on finding the equation of a plane that contains the point P(2,1,-1) and a line defined by the parametric equations x=2+t, y=4, z=-1+t. The solution involves determining two points on the line by selecting arbitrary values for the parameter t, which are then used to compute the cross product with point P. The direction vector of the line can also be utilized to simplify the process, leading to the correct equation of the plane.

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Homework Statement


Find the equation of the plane containing P(2,1,-1) and the line with equation
x=2+t
y=4
z=-1+t



Homework Equations


Cross product

The Attempt at a Solution


I understand that I need to find t and then solve for two points on the line, then find the cross product of both points with point P. I'm just confused as to how to determine the value for t, is it just arbitrary or is there a certain method that needs to be used in order to solve for the two values that I need?

Thanks!
 
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You can do it that way by choosing any two values of t to get the points. Different choices of t will give you different cross products, but they will all point in the same direction. You could also just use the direction vector for the line.
 
Thanks !
I ended up using the direction vector and the point used to create the equation of the line and then cross product to get my answer!
 

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