Equation of motion for a Mass-Spring-Damper-system, one mass 2 DOFS

Click For Summary

Discussion Overview

The discussion revolves around finding the equation of motion for a mass-spring-damper system with one mass and two degrees of freedom (DOFs). Participants explore various approaches to model the system using the state vector method, while addressing the complexities introduced by the configuration of springs and damping.

Discussion Character

  • Homework-related
  • Debate/contested
  • Exploratory
  • Mathematical reasoning

Main Points Raised

  • One participant expresses difficulty in determining the equation of motion due to the system's two degrees of freedom with only one mass.
  • Another participant questions the classification of the problem as a 2DF system, suggesting it may not be accurate.
  • A proposed method involves introducing an imaginary second mass at the connection of the springs to facilitate solving for the displacements.
  • Concerns are raised about the feasibility of using MATLAB's eig function for solving eigenvalues and eigenvectors in this context.
  • Participants discuss the significance of the displacements at the junction of the springs and the mass, leading to differing interpretations of the system's degrees of freedom.
  • One participant suggests setting up the equations of motion by considering the forces acting on both masses, with a focus on the relationship between the stretches of the springs and the position of the mass.
  • Another participant emphasizes the importance of understanding how to handle springs and dampers in series and parallel to approach the problem without introducing a second mass.

Areas of Agreement / Disagreement

Participants do not reach a consensus on whether the system should be classified as having two degrees of freedom. Multiple competing views on how to approach the problem remain, with no clear resolution on the correct method to derive the equations of motion.

Contextual Notes

Participants express uncertainty regarding the assumptions made about the system's configuration and the mathematical steps required to derive the equations of motion. The discussion highlights the complexity of modeling the system accurately given its unique setup.

Lelak
Messages
5
Reaction score
0
1. Homework Statement :

Find the equation of motion for the system below (see the attached files)
https://www.physicsforums.com/attachment.php?attachmentid=58905&stc=1&d=1369155073
Solve the problem with the state vector approach. Choose realistic values on k1,k2,c1,M and F

Homework Equations



See the attatched file.
https://www.physicsforums.com/attachment.php?attachmentid=58906&stc=1&d=1369155073

The Attempt at a Solution



I am having trouble finding the right equation of motion for this system since it has two degrees of freedom and only one mass. For a "normal", where there is a mass at every node, I have not had a problem so far.

I would appreciate any help or tips how to handle this problem! Thank you very much!
 
Last edited:
Physics news on Phys.org
Lelak said:
1. Homework Statement :

Find the equation of motion for the system below (see the attached files)
https://www.physicsforums.com/attachment.php?attachmentid=58905&stc=1&d=1369155073
Solve the problem with the state vector approach. Choose realistic values on k1,k2,c1,M and F

Homework Equations



See the attatched file.
https://www.physicsforums.com/attachment.php?attachmentid=58906&stc=1&d=1369155073

The Attempt at a Solution



I am having trouble finding the right equation of motion for this system since it has two degrees of freedom and only one mass.

Why do you say this is a 2DF problem? It isn't.
 
One way you might want to do this is to put an imaginary second mass m2 where the springs connect to each other, solve for x1 and x2, then let m2 approach zero.
 
rude man said:
One way you might want to do this is to put an imaginary second mass m2 where the springs connect to each other, solve for x1 and x2, then let m2 approach zero.

I tried doing that but then the eig function in MATLAB will not solve the eigen values and the eigenvectors. I also checked with one of the teachers, he did not seem to think that was the right way to go.
 
rude man said:
Why do you say this is a 2DF problem? It isn't.

Okay, how would you set up the equation of motion then?

I figured since there are two springs, one with damping and one without, it would be of interest to know the displacement in the node between the two springs. It would also be intereseting to find the displacement of the mass. That would give me two translations and that why I though there was 2dofs.

How would you approach this problem?
 
Lelak said:
Okay, how would you set up the equation of motion then?

I figured since there are two springs, one with damping and one without, it would be of interest to know the displacement in the node between the two springs. It would also be intereseting to find the displacement of the mass. That would give me two translations and that why I though there was 2dofs.

How would you approach this problem?

I would put a 2nd mass m at the junction of the springs. Then, when you get the result for x1 (the position of your real mass M), let m << M. I know this has to work.

So x1 is the position of real mass M when the system is quiescent (no motion of either mass), and x2 is the position of the second mass m. Then write F = mx'' for both masses, solving the system of ODE's and getting x1 and x2. Then just let m << M.

It is a 1DF system since there is motion in one direction only.

I imagine one can do without a second mass but that would involve knowledge of how to handle springs and dampers in series & parallel which I don't possess.
 
OK, there's another way: realizing that force is the same at every node from the left wall to the left end of the mass M, that gives us
k1 x1 + c dx1/dt = k2 x2 where

x1 = stretch of spring 1,
x2 = stretch of spring 2.

Let x = 0 be at the left wall;
L1 = relaxed length of spring 1
L2 = relaxed length of spring 2.

then position of mass M is at x = L1 + L2 + x1 + x2.
So now what is/are the equation(s) of motion for M? Hint: use the fact at the top of my post.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
Replies
5
Views
3K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 6 ·
Replies
6
Views
30K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 25 ·
Replies
25
Views
7K
Replies
1
Views
2K