Equation of motion for a Mass-Spring-Damper-system, one mass 2 DOFS

In summary, the student is having trouble finding the equation of motion for a system with two degrees of freedom and only one mass. They try two different methods and both fail. They eventually try to solve the system of equations using an imaginary second mass and it works.
  • #1
Lelak
5
0
1. Homework Statement :

Find the equation of motion for the system below (see the attached files)
https://www.physicsforums.com/attachment.php?attachmentid=58905&stc=1&d=1369155073
Solve the problem with the state vector approach. Choose realistic values on k1,k2,c1,M and F

Homework Equations



See the attatched file.
https://www.physicsforums.com/attachment.php?attachmentid=58906&stc=1&d=1369155073

The Attempt at a Solution



I am having trouble finding the right equation of motion for this system since it has two degrees of freedom and only one mass. For a "normal", where there is a mass at every node, I have not had a problem so far.

I would appreciate any help or tips how to handle this problem! Thank you very much!
 
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  • #2
Lelak said:
1. Homework Statement :

Find the equation of motion for the system below (see the attached files)
https://www.physicsforums.com/attachment.php?attachmentid=58905&stc=1&d=1369155073
Solve the problem with the state vector approach. Choose realistic values on k1,k2,c1,M and F

Homework Equations



See the attatched file.
https://www.physicsforums.com/attachment.php?attachmentid=58906&stc=1&d=1369155073

The Attempt at a Solution



I am having trouble finding the right equation of motion for this system since it has two degrees of freedom and only one mass.

Why do you say this is a 2DF problem? It isn't.
 
  • #3
One way you might want to do this is to put an imaginary second mass m2 where the springs connect to each other, solve for x1 and x2, then let m2 approach zero.
 
  • #4
rude man said:
One way you might want to do this is to put an imaginary second mass m2 where the springs connect to each other, solve for x1 and x2, then let m2 approach zero.

I tried doing that but then the eig function in MATLAB will not solve the eigen values and the eigenvectors. I also checked with one of the teachers, he did not seem to think that was the right way to go.
 
  • #5
rude man said:
Why do you say this is a 2DF problem? It isn't.

Okay, how would you set up the equation of motion then?

I figured since there are two springs, one with damping and one without, it would be of interest to know the displacement in the node between the two springs. It would also be intereseting to find the displacement of the mass. That would give me two translations and that why I though there was 2dofs.

How would you approach this problem?
 
  • #6
Lelak said:
Okay, how would you set up the equation of motion then?

I figured since there are two springs, one with damping and one without, it would be of interest to know the displacement in the node between the two springs. It would also be intereseting to find the displacement of the mass. That would give me two translations and that why I though there was 2dofs.

How would you approach this problem?

I would put a 2nd mass m at the junction of the springs. Then, when you get the result for x1 (the position of your real mass M), let m << M. I know this has to work.

So x1 is the position of real mass M when the system is quiescent (no motion of either mass), and x2 is the position of the second mass m. Then write F = mx'' for both masses, solving the system of ODE's and getting x1 and x2. Then just let m << M.

It is a 1DF system since there is motion in one direction only.

I imagine one can do without a second mass but that would involve knowledge of how to handle springs and dampers in series & parallel which I don't possess.
 
  • #7
OK, there's another way: realizing that force is the same at every node from the left wall to the left end of the mass M, that gives us
k1 x1 + c dx1/dt = k2 x2 where

x1 = stretch of spring 1,
x2 = stretch of spring 2.

Let x = 0 be at the left wall;
L1 = relaxed length of spring 1
L2 = relaxed length of spring 2.

then position of mass M is at x = L1 + L2 + x1 + x2.
So now what is/are the equation(s) of motion for M? Hint: use the fact at the top of my post.
 

1. What is the equation of motion for a Mass-Spring-Damper system with one mass and 2 degrees of freedom?

The equation of motion for a Mass-Spring-Damper system with one mass and 2 degrees of freedom can be written as:
m*x'' + c*x' + k*x = 0
Where m is the mass, c is the damping coefficient, k is the spring constant, and x is the displacement of the mass.

2. How do the parameters in the equation of motion affect the behavior of the system?

The mass (m) affects the inertia of the system, the damping coefficient (c) controls the rate of energy dissipation, and the spring constant (k) determines the stiffness of the system. These parameters together determine the natural frequency and damping ratio of the system, which in turn affect the amplitude and frequency of the oscillations.

3. What is the natural frequency of a Mass-Spring-Damper system with one mass and 2 degrees of freedom?

The natural frequency of a Mass-Spring-Damper system with one mass and 2 degrees of freedom is given by the formula:
ω = √(k/m)
Where ω is the natural frequency, k is the spring constant, and m is the mass.

4. What is the damping ratio and how does it affect the behavior of the system?

The damping ratio (ζ) is a dimensionless parameter that describes the level of damping in the system. It is defined as the ratio of the actual damping coefficient to the critical damping coefficient (cc). A higher damping ratio means the system is more overdamped and the oscillations will decay faster, while a lower damping ratio indicates the system is underdamped and oscillations will persist for longer.

5. How can the equation of motion be solved to find the displacement of the mass over time?

The equation of motion for a Mass-Spring-Damper system can be solved using techniques such as differential equations, Laplace transforms, or numerical methods. The solution will give the displacement of the mass as a function of time, and can be used to analyze the behavior of the system and make predictions about its future motion.

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