1. The problem statement, all variables and given/known data Find equation of plane containing points: (1,1,5),(3,5,3),(8,8,1),(10,2,2),(18,6,-1),(-1,-3,6) 2. Relevant equations Find 2 vectors given 3 points, using a common point. The cross product of these 2 vectors will be the normal vector of the plane. Use normal vector coords <a,b,c> as coefficients in the ax+by+cz=d formula where x,y,z is any point in the plane and solve for d. This equation better be true for all points. 3. The attempt at a solution P = (1,1,5) Q = (3,5,3) R = (8,8,1) PQ = <2,4,-2> PR = <7,7,-4> PQ x PR = <-2,-6,14> Plug in point P into formula and get: -2x-6y+14z = 62 Test formula by plugging in Q and don't get 62.